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netineya [11]
2 years ago
10

How many 5 digit flippy numbers are divisible by 15.

SAT
1 answer:
marishachu [46]2 years ago
3 0

Answer:

4

Explanation:

Since it's a flippy number, we can set each digit into ababa

Since it can be divisible by 15, which means it can be divisible by both 5 and 3.

Since it is divisible by 5, the last digit will be either 0 and 5, but it cannot be 0 because 0 cannot be the first digit, so last digit must be 5.

So, ababa --> 5b5b5

It can also be divisible by 3. According to de divisibility rule of 3, if the sum of all digit is divisible by 3 then the number is divisible by 3.

Sum of all digits = 15 + 2b

it's divisible by 3 when b = 0,3,6,9

The answer is 4.

There are 4 such number.

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Factor the expression into an equivalent form 12y^2-75.
elena-14-01-66 [18.8K]

Hello oddworld7836!

\huge \boxed{\mathbb{QUESTION} \downarrow}

Factor the expression into an equivalent form 12y² - 75.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

12 y ^ { 2 } - 75

By observing the expression, we can see that, 3 is the only common factor in both the terms of the expression. So, take the common factor 3 out.

12 y ^ { 2 } - 75 \\  = 3\left(4y^{2}-25\right)

Now, look at (4y² - 25). They don't have any common factors but they appear in the form of the algebraic identity ⇨ a² - b² = (a + b) (a - b). Here,

  • a² = 4, a = 2 (√a² = ✓4 = 2)
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So, the (4y² + 25) becomes...

(4 {y}^{2}  - 25) \\  = \left(2y-5\right)\left(2y+5\right)

Now, bring the 3 (common factor) & rewrite the complete expression.

12 y ^ { 2 } - 75 \\  =  \boxed{ \boxed{ \bf \: 3\left(2y-5\right)\left(2y+5\right) }}

We can't further simplify it. Also, remember that the simplified form of an expression is equivalent to the expression. So, 3 (2y - 5) (2y + 5) is equivalent to 12y² - 75.

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Answer:

Explanation:

What is the radius or diameter? I can't help you without that.

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Why do we want to know how much and type of precipitation?
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Answer:

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Newton’s law of cooling states that for a cooling substance with initial temperature t0, the temperature t(t) after t minutes ca
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The cooling rate of the substance is approximately 0.0732.

According to the statement, the Newton's law of cooling is defined by the following formula:

T(t) = T_{s} + (T_{o}-T_{s})\cdot e^{-k\cdot t} (1)

Where:

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  • T_{o} - Initial temperature, in degrees Celsius.
  • t - Time, in minutes.
  • k - Cooling rate, in \frac{1}{min}.
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Please notice that substance reaches thermal equilibrium when T(t) = T_{s}, that is when temperature of the substance is equal to the temperature of surrounding air.

If we know that T_{o} = 80\,^{\circ}C, t = 15\,min, T_{s} = 50\,^{\circ}C and T(15) = 60\,^{\circ}C, then the cooling rate of the substance is:

60 = 50 + (80 - 50)\cdot e^{-15\cdot k}

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k = -\frac{1}{15}\cdot \ln \frac{1}{3}

k \approx 0.0732

The cooling rate of the substance is approximately 0.0732.

To learn more on Newton's law of cooling, we kindly invite to check this verified question: brainly.com/question/13748261

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