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kogti [31]
2 years ago
15

In a group of 20 students, 5 of them wear

Mathematics
1 answer:
il63 [147K]2 years ago
8 0

Answer:

15 of them do not wear glasses

Step-by-step explanation:

20-5=15

Hope this helps. Have a great day :)

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You mow the lawn to earn your allowance. Each time you mow the lawn you earn \$12$12dollar sign, 12. Write an equation for the n
horrorfan [7]
For this case, the first thing we must do is define variables.
 m: number of times you cut the grass
 d: amount of dollars you earn.
 We now write the linear equation that models the problem:
 d = 12m
 The slope of the line is 12, which means that each time you cut the grass, you earn 12 dollars.
 Answer:
 
an equation for the number of dollars, d, you earn when you mow the lawn m times is:
 
d = 12m
6 0
3 years ago
Which ordered pair is a solution of the equation?<br> y = -6x+1
alekssr [168]

Answer:

2,-11

Step-by-step explanation:

create an x/y table and plug in #s for ordered pairs

-6x + 1 = y [plug in 2 for x]

-12 + 1 = -11 [ordered pair is 2, -11]

7 0
3 years ago
Read 2 more answers
a vido game system is being sold at a 4% discount. if the discount results in a saving of$11,96, what is the original price of t
kramer

Answer:

$299

Step-by-step explanation:

Divide the discount amount through the discount percentage and multiply with a hundred percent, resulting in the full price.

($11,96)/4*100=$299

8 0
3 years ago
Using technology, determine the monthly payment on a 35 month loan of $28,000 at 8.1% compounded annually. Round you answer to t
sdas [7]
Present Value of an annuity is given by the formular
PV = P(1 - (1 + r)^-n)/r; where PV = $28,000, r = 0.081/12 = 0.00675, n = 35 and P is the periodic (monthly) payment.

P = PVr/(1 - (1 + r)^-n) = (28,000 x 0.00675)/(1 - (1 + 0.00675)^-35) = 189/0.2098 = 900.90

Therefore, the monthly payment is $900.90
7 0
3 years ago
3)<br> Solve the quadratic equation by taking square roots.<br> 3x^2 – 8 = 12
iris [78.8K]

Answer:

The answer is in the photo

Step-by-step explanation:

8 0
3 years ago
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