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3 years ago

Of the 200 students surveyed in 5th grade, 120 prefer banana and 80 prefer apples what is the part to part ratio

Mathematics

1 answer:

drek231 [11]3 years ago

5 0

3/2 because you simplify 120/80 and you get 3/2

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Suppose a basketball player has made 390 out of 434 free throws. If the player makes the next 2 free throws, I will pay you $40.

alukav5142 [94]

Answer: a) -$0.19, b) -$111.72 .

Step-by-step explanation:

Since we have given that

Number of free throws = 434

Number of throws made by them = 390

Amount for making the next 2 free throws = $40

Amount otherwise he has to pay = $169

a) Find the expected value of the proposition.

Expected value of success in next 2 free throws = $\dfrac{390}{434}\times \dfrac{391}{435}=0.8077$

Expected value would be

$0.8077\times 40+(1-0.8077)\times -169\\\\=32.308-32.4987\\\\=-\$0.19$

b) If you played this game 588 times how much would you expect to win or lose?

Number of times they played the game = 588

So, Expected value would be

$588\times -0.19\\\\=-\$111.72$

Hence, a) -$0.19, b) -$111.72

8 0

3 years ago

Multiply

Paraphin [41]

Answer:

B. 20x^4-39x^3+26x^2-6x

Step-by-step explanation:

(5x^2-6x+2)*(4x^2-3x)

20x^4 -15x^3 -24x^3 + 18 x^2 +8x^2 - 6x

20x^4 -39x^3 + 26x^2 - 6x

5 0

2 years ago

Graph system of inequalities <br> Y>|2/3x-3<br> Y>|-4/3x+3

quester [9]

The Graphs are in attachment !

1st graph is for equation :

$y > \dfrac{2}{ 3}x - 3$

2nd graph is for equation :

$y > - \dfrac{4}{3} x + 3$

7 0

3 years ago

Read 2 more answers

[WILL GIVE BRAINLIEST]

kirill115 [55]

Your answer is simple times 6 to 3 to get 18 then 15 by 8 to get 96 then add up everything to get 114

6 0

3 years ago

A pet shop manager wants the same number of birds in each cage he wants to use as few cages as possible but he can only have one

anastassius [24]

Since there are more parakeets than canaries, it is not possible to have only 1 of each bird in each cage <u>and</u> have the same number of birds in each cage.

He could use 42 cages, putting a canary in with the parakeet in 18 of them. Then he would have 18 cages with 2 birds each, and 24 cages with 1 bird each.

The only way to have the same number of birds (1) in all cages is to have 60 cages, 42 of which have 1 parakeet, and 18 of which have 1 canary.

_____

If more than 1 of each kind of bird can be put in the cage, the collection of birds could be put into 6 cages, each of which would be home to 7 parakeets and 3 canaries.

4 0

3 years ago