Help me get the anwser to this Equation
1 answer:
Answer:
The answer depends on x.value
Step-by-step explanation:
I. It's linear equation
y = mx + b
when y is output, x is input, m is slope and b is addition
So if x = -1
y = -4/3(-1) - 2
= 4/3 - 2
= (4-6)/3
y = -2/3
It will be something like this (-1, -2/3) when -1 is x.value, -2/3 is y.value
You can given x.value be anything like 0, 1, 2, 3 the graph will be like this
(Picture is only example)
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Answer:
The height of the ball after 3 secs of dropping is 16 feet.
Step-by-step explanation:
Given:
height from which the ball is dropped = 160 foot
Time = t seconds
Function h(t)=160-16t^2.
To Find:
High will the ball be after 3 seconds = ?
Solution:
Here the time ‘t’ is already given to us as 3 secs.
We also have the relationship between the height and time given to us in the question.
So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:
h(3)=160-144
h(3)=16
Therefore, the height of the ball after 3 secs of dropping is 16 feet.