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nataly862011 [7]
2 years ago
6

Solve 8(12−14x)≥82. Show your steps.

Mathematics
1 answer:
saveliy_v [14]2 years ago
7 0

Answer:

x ≤ 1/8

Step-by-step explanation:

Expand the parentheses

Simplify the arithmetic

Solve by distributing

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Half of your baseball card collection got wet and was ruined. You bought 9 cards to replace some that were lost. How many did yo
PtichkaEL [24]

solution:

n/2 + 9 = 20

n/2=20-9

n/2=11

n=22

6 0
3 years ago
Jarvis left out a statement from the proof shown.which statement is best explained by the corresponding angles postulate
Salsk061 [2.6K]
The postulate of the corresponding angles establishes that when a transversal line cuts two parallel lines, the corresponding angles are congruent. These angles are on the same side of the parallel lines and on the same side of the transversal line.

  Then, if we based on this definition and analize the figure attached, we can notice that the angles ∠1 and ∠3 are corresponding angles, so they are congruent. In this case the angle ∠1 is internal and the angle ∠3 is external.

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7 0
3 years ago
Read 2 more answers
Q # 4 anybody help me please
Marysya12 [62]

<u>Answer</u>

-5/3, -1,  0.7,  √2,   √5


<u>Explanation</u>

√5 = 2.236

-1 ⇒ this is less than 1.  

-5/3 = -1.666667    this is less than 1.  -5/3 < -1

0.7 > -1

√2 = 1.414        ⇒     √5 > √2

Arranging them from the least to the greatest;

-5/3, -1,  0.7,  √2,   √5

8 0
3 years ago
Find the product of<br> (-2 x5y3 )( 3x2y )
Y_Kistochka [10]

Answer:

(-2 x5y3 )( 3x2y )= -180 x2 y2

7 0
2 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
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