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igomit [66]
3 years ago
12

Convert 30 ft to cm .......................................

Biology
1 answer:
Anon25 [30]3 years ago
6 0
914.4 cm……………………………..
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D Learning Task No.2: Use the GRESA Method in solving the problem below. Show your solutions. Write your answers in your noteboo
lina2011 [118]

GRESA method stands for given, required, equation, solution and answer.

We are required to solve the question according to the GRESA method. However, the question has multiple sub questions and hence we will solve each one of them separately.

Question 1:

Given:

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initial velocity is 0 m/s

final velocity is 40 m/s

time is given to be 10 s

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We are required to find the mass of the cart.

Equation:

By using Newton's second law of motion,

F= m x (v-u)/t

Solution:

By putting all the values, we get:

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Hence option (c) 50kg is correct

QUESTION 2:

Given:

mass of ball = 0.4 kg

force of hitting = 16N

Required:

We are required to find the acceleration of the ball after hitting

Equation:

Using Newton's law of motion,

F = m x a

Solution:

By putting all the values, we get:

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a =16/0.4 = 40 m/s^2

Answer:

Hence option (B) 40 m/s^2 is the correct answer

QUESTION 3:

Given:

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acceleration of papaya = 2.2 m/s^2

Required:

We are required to find the net force applied

Equation:

Using Newton's law of motion,

F = m x a

Solution:

By putting all the values we get:

F = 3.5 x 2.2

  =7.7 N

Answer:

The external force applied is 7.7 N to the left

Question 4:

Given:

net force = 300N

acceleration = 0.750 m/s^2

Required:

We are required to find the mass of the crate

Equation:

By using Newton's second law of motion,

F= m x a

Solution:

By putting all the values, we get:

300 = m x 0.750

m = 300/0.750

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Answer:

Hence the weight of crate is 400kg

#SPJ9

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A rise in the partial pressure of carbon dioxide will cause a __________ in ph and a __________ in blood bicarbonate levels.
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fall & rise.. The initial compensating response to an acute respiratory alkalosis is a modest decline in ECF bicarbonate concentration as the result of cellular buffering. Subsequent renal responses result in decreased ECF bicarbonate concentration through reduced renal bicarbonate reabsorption.

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At the complete end of cellular respiration, how many molecules of ATP are produced?
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Hello! The answer to your question would be as followed:

<u><em>A. 38 molecules of ATP are produced</em></u>

<u><em></em></u>

The ATP yield during aerobic respiration isn't 36-38, but only about 30-32 ATP molecules/ 1 molecule of glucose.

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