9 pls pls pls help meeee!

Plz, help ASAP!!!!!!<br> WILL MARK BRAINLIEST IF YOUR ANSWER IS CORRECT!!!!!!

Mekhanik [1.2K]

Blank 1: Given

Blank 2 : AD is parallel to BC

Blank 3: <3≅<2

Blank 4: Transitive property of convergence

Blank 5: Definition of Bisect

Step-by-step explanation:

We need to fill in the blanks from the given options.

Blank 1:

ABCD is a parallelogram

This is given

So, blank 1: Given

Blank 2:

A parallelogram have parallel sides i.e in the given parallelogram AD is parallel to BC and AB is parallel to DC

So, Blank 2 : AD is parallel to BC

Blank 3:

We are given <3≅<2

So, Blank 3: <3≅<2

Blank 4:

We know, <1≅<3 and <3≅<2 using transitive property (A≅B and B≅C then A≅C)

So, <1 ≅ <2 is due to transitive property of convergence

Blank 4: Transitive property of convergence

Blank 5:

DC bisects <ADE

A bisect is an line or angle that divides into exactly two parts.

So, Blank 5: Definition of Bisect

Keywords: parallelogram, bisection

Learn more about parallelogram at:

#learnwithBrainly

4 0

3 years ago

Calculate dy/dx when xy^3 + y =3x

Brilliant_brown [7]

You have to use implicit derivative

dy / dx = y'

xy^3+y=3x

y^3 + 3xy^2 y' + y' = 3

[3xy^2 + 1) y'= 3 - y^3

          3 - y^3
y' = -----------------   <-----------answer
         3xy^2 + 1

6 0

2 years ago

Write the equation of a line that passes through the points (−3, 7) and (3, 3)

Dennis_Churaev [7]

Step-by-step explanation:

You can write an equation of a line conveniently by point-slope form. It's in the form of $y -a = m(x -b)$ where $(b,a)$ is the coordinates of a point that's on the line and $m$ is the slope of the line.

Now choose a point (It doesn't really matter which one) and plug that in the equation. I'll choose $(-3,7)$ where $a = 7$ and $b = -3$

$y -a = m(x -b) \\ y -7 = m(x -(-3)) \\ y -7 = m(x +3)$

The next thing we have to do now is finding the slope, $m$ , where it's equal to $\frac{y_{2} -y_{1}}{x_{2} -x_{1}}\\$ . I'll make $(-3,7)$ point 1 and $(3,3)$ point 2.

$m = \frac{3 - 7}{3 -(-3)} \\ m = \frac{3 - 7}{3 +3} \\ m = \frac{-4}{6} \\ m = -\frac{2}{3}$

Now let's plug that to our equation.

$y -7 = m(x +3) \\ y -7 = -\frac{2}{3}(x +3)$

Now we have the equation but out of all the choices it seemed that all of them are in slope-intercept form all you have to do now is make our equation rewrite it in slope-intercept form.

$y -7 = -\frac{2}{3}(x +3)\\ y -7 = -\frac{2}{3}x -\frac{2}{3}(3) \\ y - 7 = -\frac{2}{3}x -2\\ y = -\frac{2}{3}x +5$

<h3>Answer:</h3>

$y = -\frac{2}{3}x +5\\$ is your equation.

3 0

2 years ago

What is the answer to 2(x+1)<x+3

Temka [501]

2x+2 < x+3
2x-x < 3-2
x <1

5 0

2 years ago

OM , ON and OP are the angle bisectors of ∠AOB, ∠BOC, and ∠COD respectively. ∠AOD and ∠BOE are straight angles.

Orlov [11]

Find m∠BOC, if m∠MOP = 110°.

Answer:

m∠BOC= 40 degrees

Step-by-step explanation:

A diagram has been drawn and attached below.

OM bisects AOB into angles x and x respectively
ON bisects ∠BOC into angles y and y respectively
OP bisects ∠COD into angles z and z respectively.

Since ∠AOD is a straight line

x+x+y+y+z+z=180 degrees

$2x+2y+2z=180^\circ$

We are given that:

m∠MOP = 110°.

From the diagram

∠MOP=x+2y+z

Therefore:

x+2y+z=110°.

Solving simultaneously by subtraction

$2x+2y+2z=180^\circ$

x+2y+z=110°.

We obtain:

x+z=70°

Since we are required to find ∠BOC

∠BOC=2y

Therefore from x+2y+z=110° (since x+z=70°)

70+2y=110

2y=110-70

2y=40

Therefore:

m∠BOC= 40 degrees

3 0

2 years ago