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Morgarella [4.7K]
3 years ago
6

Shannon swam 100 meters in 56.24 seconds. Rick swam 100 meters

Mathematics
1 answer:
ahrayia [7]3 years ago
5 0

Answer:

find the difference between the two times by subtracting them;

59.48-56.24= 3.24 seconds

Step-by-step explanation:

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Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
Help me please!!! And thank you!!!!
katen-ka-za [31]
<h2>Answer:</h2>

The last answer - 9x squared y squared

<h2></h2>

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What is one benefit to lifelong physical activity? healthier diet lower risk of stroke organized daily schedule lower chance of
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Please explain how they plugged the removable discontinuity in this question.
kondor19780726 [428]

In the limit

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we're interested in the value that f(x) converges to as x gets closer to c. So in fact x\neq c.

In the given example, f(x) is factorized to reveal a common factor of x-1 in the numerator and denominator. We have x\neq1 if x\to1, so x-1\neq0 so we can simplify

\dfrac{x-1}{x-1} = 1

and *remove* the discontinuity.

Then

\displaystyle \lim_{x\to1} \frac{2(x-1)}{(x+1)(x-1)} = \lim_{x\to1} \frac2{x+1} = \frac2{1+1} = 1

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2 years ago
Solve for y. <br><br> y-260=-11/5*(x-60)
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its -325

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