the perimeter of a triangle is 38 ft . One side is 14 ft long . Another side is 9 ft long . How long is the third side ?

A management company opens a large apartment complex in anticipation of growth in the community. The company compiles statistics

bezimeni [28]

The equation is given to us in slope intercept form. -34.85 is the slope and the y-intercept is 938.

Therefore, we can say:
The rate of change for the line of best fit is -34.85 which represents the decrease in number of available apartments per week since the complex opened.
The y-intercept is 938 which represents the number of apartments when it first opened.

7 0

3 years ago

The box plots show the weights, in pounds, of the dogs in two different animal shelters.

zimovet [89]

*see attachment below for the box plots that is being referred to

Answer:

*The median weight for shelter A is greater than that for shelter B

*The data for shelter B are a symmetric data set

Step-by-step explanation:

Let's take each stated option and examine the box plot to see which is TRUE or NOT.

OPTION 1: "The median weight for shelter A is greater than that for shelter B."

The median for shelter A = 21,

Median for shelter B = 18

Median weight for shelter A (21) is greater than that for shelter B.

This statement in this option is TRUE.

OPTION 2: "The median weight for shelter B is greater than that for shelter A."

Median for B (18) < median of A (21)

This statement in option is NOT TRUE.

OPTION 3: "The data for shelter A are a symmetric data set."

This is NOT TRUE because the length of both whiskers are unequal and also, the box is not divided equally. One side is longer than the other.

OPTION 4: "The data for shelter B are a symmetric data set."

This is TRUE because the length of both whiskers are relatively equal, and also, the rectangular box is divided equally.

OPTION 5: "The interquartile range for shelter A is 8"

This is NOT TRUE.

IQR = Q3-Q1

IQR for shelter A is approximately = 28-17 = 11

5 0

3 years ago

A line m is perpendicular to an angle bisector of ∠A. The sides of ∠A intersect this line m at points M and N. Prove that △AMN i

Ray Of Light [21]

Answer:

Step-by-step explanation:

Given: A line m is perpendicular to the angle bisector of ∠A. We call this

intersecting point as D. Hence, in figure ∠ADM=∠ADN =90°.

AD is angle bisector of ∠A. Hence, ∠MAD=∠NAD.

To Prove: ΔAMN is an isosceles triangle. i.e any two sides in ΔAMN are

equal.

Solution: Now, In ΔADM and ΔADN

∠MAD=∠NAD ...(1) (∵Given)

AD=AD ...(2) (∵common side)

∠ADM=∠ADN ...(3) (∵Given)

Hence, from equation (1),(2),(3) ΔADM ≅ ΔADN

( ∵ ASA congruence rule)

⇒ AM=AN

Now, In Δ AMN

AM=AN (∵ Proved)

Hence, ΔAMN is an isosceles triangle.

7 0

3 years ago

Angie has already written 19 pages, and she expects to write 1 page for every additional

marta [7]

Answer:

$9$

Step-by-step explanation:

$28 - 19 = 9$

7 0

3 years ago

Read 2 more answers

8. Hassan made a vegetable salad with 2 3/8 pounds

amm1812

let's convert firstly the mixed fractions to improper fractions and then add up.

$\bf \stackrel{mixed}{2\frac{3}{8}}\implies \cfrac{2\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{19}{8}}~\hfill \stackrel{mixed}{1\frac{1}{4}}\implies \cfrac{1\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{5}{4}} \\\\\\ \stackrel{mixed}{2\frac{7}{8}}\implies \cfrac{2\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{23}{8}} \\\\[-0.35em] ~\dotfill$

$\bf \cfrac{19}{8}+\cfrac{5}{4}+\cfrac{23}{8}\implies \stackrel{\textit{using an LCD of 8}}{\implies \cfrac{(1)19+(2)5+(1)23}{8}}\implies \cfrac{19+10+23}{8} \\\\\\ \cfrac{52}{8}\implies \cfrac{13}{2}\implies 6\frac{1}{2}$

5 0

3 years ago