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inessss [21]
3 years ago
9

A thermometer falls from a weather

Mathematics
1 answer:
Nesterboy [21]3 years ago
6 0

Answer:

It will take 22 seconds for the thermometer to hit the ground.

Step-by-step explanation:

A thermometer falls from a weather balloon at a height of 7,744 ft.

This means that the initial height is of 7744ft.

h(t) = -16t2 + initial height

So

h(t) = -16t^2 + 7744

How many seconds will it take for the thermometer to hit the ground?

This is t for which h(t) = 0. So

0 = -16t^2 + 7744

16t^2 = 0 + 7744

t^2 = \frac{7744}{16}

t = \sqrt{\frac{7744}{16}}

t = 22

It will take 22 seconds for the thermometer to hit the ground.

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inna [77]
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You can try an example of this with (1, 0, 0), (0, 1, 0), and (0, 0, 1), the usual basis vectors of R3.
That method relied on spotting the solution immediately.If you couldn’t see that, then there’s another approach to the problem.
We know that u, v, w are linearly independent vectors.So if au + bv + cw = 0, then a, b, and c are all 0 by definition.
Suppose we wanted to ask whether u – v, v – w, and u – w are linearly independent.Then we’d like to see if there are non-zero coefficients in the linear combinationd(u – v) + e(v – w) + f(u – w) = 0, where d, e, and f are scalars.
Distributing, we get du – dv + ev – ew + fu – fw = 0.Then regrouping by vector: (d + f)u + (-d +e)v + (-e – f)w = 0.
But now we have a linear combo of u, v, and w vectors.Therefore, all the coefficients must be 0.So d + f = 0, -d + e = 0, and –e – f = 0. It turns out that there’s a free variable in this solution.Say you let d be the free variable.Then we see f = -d and e = d.
Then any solution of the form (d, e, f) = (d, d, -d) will make (d + f)u + (-d +e)v + (-e – f)w = 0 a true statement.
Let d = 1 and you get our original solution. You can let d = 2, 3, or anything if you want.

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3 years ago
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For this case we must find the inverse of the following function:

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For this, we follow the steps below:

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We exchange the variables:

x = 8 \sqrt {y}

We solve for y:

8 \sqrt {y} = x

We divide between 8 on both sides of the equation:

\sqrt {y} = \frac {x} {8}

We raise both sides of the equation to the square to remove the root:

y = (\frac {x} {8}) ^ 2\\y = \frac {x ^ 2} {64}

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Answer:

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allochka39001 [22]

Answer:

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The only apparent transformation is negation of the y-coordinate, corresponding to reflection across the x-axis.

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