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LekaFEV [45]
1 year ago
11

Explain how to use the discriminant to determine the number and type of roots of a quadratic equation.

Mathematics
1 answer:
baherus [9]1 year ago
8 0

The general form of the quadratic equation is :

ax^2+bx+c=0

The discriminant is :

D=b^2-4\cdot a\cdot c

And the general solution is :

x=\frac{-b\pm\sqrt[]{D}}{2\cdot a}

So, there are 3 situations for D

1. D = 0

So, the roots of a quadratic equation are two similar roots

2. D > 0

so, roots of a quadratic equation are two different roots

3. D < 0

so, roots of a quadratic equation are not real, two comlex roots

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ryzh [129]
Follow PEMDAS.

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Alright, do multiplication first, then division. Then, do subtraction then addition.

7-1*0+3/3= \\ 7-0+3/3= \\ 7 - 0 + 1= \\ 7 + 1 = 8 \\ 7-1*0+3/3 =8

Hope this helped!
6 0
3 years ago
Help with Math PLZ (Questions in screenshot)
-Dominant- [34]

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2.) For inequalities such as these, you can simplify just like what you do for normal equations. Let's isolate x.

x - 7 > 10

--> x > 10 + 7

---> x > 17

3.) 3x \leq 21

--> \frac{3x}{3} \leq  \frac{21}{3}

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4.) 5a - 2 < 18

--> 5a < 18 + 2

---> 5a < 20

----> \frac{5a}{5} < \frac{20}{5}

-----> a < 4

5.) 2t + 8 \geq -4(t + 1)

--> 2t + 8 \geq -4t - 4

---> 2t + 4t \geq -8 - 4

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7 0
3 years ago
HELP PLEASEEEEEEEE TYY
emmasim [6.3K]

Answer:

1. -3

2. 5

Step-by-step explanation:

Hope this helped

Also Toga is my favorite character

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