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LekaFEV [45]
1 year ago
11

Explain how to use the discriminant to determine the number and type of roots of a quadratic equation.

Mathematics
1 answer:
baherus [9]1 year ago
8 0

The general form of the quadratic equation is :

ax^2+bx+c=0

The discriminant is :

D=b^2-4\cdot a\cdot c

And the general solution is :

x=\frac{-b\pm\sqrt[]{D}}{2\cdot a}

So, there are 3 situations for D

1. D = 0

So, the roots of a quadratic equation are two similar roots

2. D > 0

so, roots of a quadratic equation are two different roots

3. D < 0

so, roots of a quadratic equation are not real, two comlex roots

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I need help with this plz
Anni [7]

Answer:

exponent of x is 33

exponent of y is 0

Step-by-step explanation:

you need to combine all powers (exponents) of x, and all exponents of y separately.

remember : x to the power of a divided by x to the power of b is x to the power of (a-b).

when multiplying, the "-" turns into a "+".

so, we have actually for x the exponent calculation :

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and for the y exponents

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2 years ago
Given: f(x) = x - 7 and h(x) = 2x + 3
LenKa [72]

<u>ANSWER</u>


h(f(x))=2x-11


<u>EXPLANATION</u>


Given f(x)=x-7


and

h(x)=2x+3


We want to find


h(f(x))=h(x-7)

This means we substitute the function f in to another function h and evaluate.

This implies that;

h(f(x))=2(x-7)+3


We expand the parenthesis to obtain;


h(f(x))=2x-14+3

We simplify further to obtain;

h(f(x))=2x-11


Hence the correct answer is A

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