Answer:
24... I hoped dis helped.
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
It’s A letter A hope this helped
We are given
speed=0.013 m/s
so, we can also write as
now, we can change it into miles/hour
so, we know that
1mile =1609.34 m
now, we can find for 1m
we know that
we can write our speed as
we can plug values
now, we can simplify it
so, we get
...........Answer
Answer:
Step-by-step explanation:
1)=-2
2)=18
3)=2.5
