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mel-nik [20]
3 years ago
14

The sum of 3 consecutive numbers is 126. Find the numbers.

Mathematics
2 answers:
anzhelika [568]3 years ago
7 0

Answer:

Hello!!

The sum of 3 constructive numbers is 126. The three constructive numbers are...

41+42+43=126

Hope this helps!!

Fittoniya [83]3 years ago
4 0

Answer:

I would say 41, 42, and 43. Because these are all consecutive numbers that add up to 126.

Step-by-step explanation:

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The sum of three consecutive integers is 198. What are the​ integers?
-BARSIC- [3]

Answer:

The sum of three consecutive integers for 198 are <em>65, 66, and 67</em>

Definition of "INTEGERS"

1.  a whole number; a number that is not a fraction.

2. a thing complete in itself.

Step-by-step explanation:

198 = x + x + 1 + <em>x + 2</em>

combine like numbers

198 = 3x + 3

subtract 3 from like numbers (in this case)

198 - 3 = 3x + 3 - 3

195 = 3x

divide by 3

195/3 = 3x/3

65 = x

x + 1 = 65 + 1  ---66

x + 2 = 65 +2  --67

6 0
3 years ago
Which choice is equivalent to the quotient shown here when x is greater than or equal to 0?
Dima020 [189]

Answer: OPTION C

Step-by-step explanation:

Remember that:

\sqrt[n]{a^n}=a

And the Product of powers property establishes that:

a^m*a^n=a^{(mn)}

Rewrite the expression:

\frac{\sqrt{18x} }{\sqrt{32} }

Descompose 18 and 32 into their prime factors:

18=2*3*3=2*3^2\\32=2*2*2*2*2=2^5=2^4*2

Substitute into the expression, then:

\frac{\sqrt{(2*3^2)x} }{\sqrt{2^4*2} }

Finally,simplifying, you get:

\frac{3\sqrt{(2)x} }{2^2\sqrt{2} }=\frac{3\sqrt{2x}}{4\sqrt{2}}=\frac{(3)(\sqrt{x})(\sqrt{2})}{(4)(\sqrt{2})}= \frac{3\sqrt{x}}{4}

8 0
3 years ago
-3+4x-10=1/2x<br><br> Please HELP
vesna_86 [32]

Answer:

x=26/7

Step-by-step explanation:

3 0
3 years ago
What property of equality is X-12=7
Andreyy89
The property of equality equal Nineteen
8 0
3 years ago
You move up 4 units and right 2 units. You end at (-1, 3). Where did you start?
Delicious77 [7]

Answer:

at the begining

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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