1/2(16+22)
= 1/2 (38)
= 19
the length if the midsegment is 19
I'm pretty sure...
Answer:
15th term =29/3
16th term = 31/3
Step-by-step explanation:
Given an arithmetic sequence with the first term a1 and the common difference d , the nth (or general) term is given by an=a1+(n−1)d .
First we find the 15th term
n=15
a1=1/3
d=1 - 1/3 = 2/3
Solution
1/3+(15-1)2/3
1/3+28/3
(1+28)/3
29/3
Lets find the 16th term
1/3+(16-1)2/3
1/3+30/3
(1+30)/3
31/3
Answer:
- y=0.8x
- See Explanation for others
Step-by-step explanation:
The 3 cans of beans had a total weight of 2.4 Pounds
Therefore:
- 1 can of beans = (2.4 ÷ 3) =0.8 Pounds
The following applies from the options.
- y=0.8x where y is the weight and x is the number of cans.
- A 2-column table with 3 rows. Column 1 is labeled number of cans with entries 5, 15, 20. Column 2 is labeled total weight (in pounds) with entries 4, 12, 16.
Using y=0.8x
When x=5, y=0.8 X 5=4
When x=15, y=0.8 X 15=12
When x=20, y=0.8 X 20=16

- On a coordinate plane, the x-axis is labeled number of cans and the y-axis is labeled total weight (in pounds. A line goes through points (5, 4) and (15, 12). This can be clearly seen from the table above as (5,4) and (15,12) are points on the line.
U should have subtract 180 and 131