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Vanyuwa [196]
3 years ago
10

PLEASE HELP IF YOU HELP ME ILL MARK YOU AS BRAINIEST

Mathematics
2 answers:
expeople1 [14]3 years ago
5 0

Answer:

B

Step-by-step explanation:

salantis [7]3 years ago
3 0

Answer:

4.8 B

Step-by-step explanation:

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4. Use the substitution method to determine the solution to this system of equations.
N76 [4]

Answer:

No solution

Step-by-step explanation:

6X - 3Y = -9--------------(1)

- 2 X +Y= 5---------------(2)

from equation two,

Y = 5+2X------------------(3)

substitute equation (3) into equation (1)

6X-3(5+2X)= -9

opening bracket

6X-15-6X= -9

6X- 6X = -9+15

0 = 6

<h2>therefore the answer is no solution</h2>

3 0
2 years ago
Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
3 years ago
Solve the following quadratic equation. *<br> x^2+12x-45=0
liq [111]

Answer:

9 over 5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Two times the sum of a number and three is not equal to eight
jarptica [38.1K]
Could be the sum is 1 and then 2 times 2 which equals 4 then 5 then plus 3 it is 8 so wrong
8 0
3 years ago
What is the rule for this sequence 6, 18, 54, 162, 486
ahrayia [7]
Multiply the number by 3
3 0
3 years ago
Read 2 more answers
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