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Vanyuwa [196]
3 years ago
10

PLEASE HELP IF YOU HELP ME ILL MARK YOU AS BRAINIEST

Mathematics
2 answers:
expeople1 [14]3 years ago
5 0

Answer:

B

Step-by-step explanation:

salantis [7]3 years ago
3 0

Answer:

4.8 B

Step-by-step explanation:

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A researcher records the change in weight (gained or lost) during the first semester of college for each individual in a group o
german

Answer:

Statistic

Step-by-step explanation:

Generally, when we talk about statistic, we are talking about the characteristic of a sample. A statistic can be said to be a value which is calculated or computed from the values in a sample.

By applying mathematical functions in this case addition and division to the values present in the sample, we have what is now known as statistic.

6 0
3 years ago
What is the value of x in the equation 1.5(x + 4) – 3 = 4.5(x – 2)?
rjkz [21]
Hello!

Step 1: Simplify both sides of the equation.<span><span><span>
1.5<span>(<span>x+4</span>)</span></span>−3</span>=<span>4.5<span>(<span>x−2</span>)</span></span></span><span><span><span><span><span><span>

(1.5)</span><span>(x)</span></span>+<span><span>(1.5)</span><span>(4)</span></span></span>+</span>−3</span>=<span><span><span>(4.5)</span><span>(x)</span></span>+<span><span>(4.5)</span><span>(<span>−2</span>)</span></span></span></span>(Distribute)<span><span><span><span><span>

1.5x</span>+6</span>+</span>−3</span>=<span><span><span>4.5x</span>+</span>−9</span></span><span><span><span>

(<span>1.5x</span>)</span>+<span>(<span>6+<span>−3</span></span>)</span></span>=<span><span>4.5x</span>−9</span></span>(Combine Like Terms)<span><span><span>

1.5x</span>+3</span>=<span><span>4.5x</span>−9</span></span><span><span><span>
</span></span></span>Step 2: Subtract 4.5x from both sides.<span><span><span><span>

1.5x</span>+3</span>−<span>4.5x</span></span>=<span><span><span>4.5x</span>−9</span>−<span>4.5x</span></span></span><span><span><span>

−<span>3x</span></span>+3</span>=<span>−9</span></span>

Step 3: Subtract 3 from both sides.<span><span><span><span>

−<span>3x</span></span>+3</span>−3</span>=<span><span>−9</span>−3</span></span><span><span>

−<span>3x</span></span>=<span>−12</span></span>

Step 4: Divide both sides by -3.<span><span><span>

−<span>3x</span></span><span>−3</span></span>=<span><span>−12</span><span>−3</span></span></span><span>

x=<span>4

Hope this helps! Cheerio, and have a lovely day!</span></span>
7 0
3 years ago
Read 2 more answers
Cassie received a 20%-off coupon and a $10-off coupon from a department store. She visits the department store during a tax-free
UNO [17]

Answer:

  B.  The original purchase total must be at most to $44 before the discounts are applied.

Step-by-step explanation:

Solve the inequality by adding $10, then dividing by 0.8.

  0.8x -$10 ≤ $25.20

  0.8x ≤ $35.20 . . . . . . . . add $10

  x ≤ $35.20/0.8 . . . . . . . divide by 0.8

  x ≤ $44 . . . . . . . . . the before-discount purchase must be at most $44

4 0
3 years ago
The sum of a number x and 5 equals 14.
Fudgin [204]
Sum means addition so the equation is x+5=14

To get the answer, just do 14-5 and the answer is 9
4 0
3 years ago
Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an
Leya [2.2K]
Parameterize the lateral face T_1 of the cylinder by

\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v

where 0\le u\le2\pi and 0\le v\le3, and parameterize the disks T_2,T_3 as

\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)
\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)

where 0\le r\le2 and 0\le\theta\le2\pi.

The integral along the surface of the cylinder (with outward/positive orientation) is then

\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS
=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr
=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr
=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr
=136\pi
7 0
3 years ago
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