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Sedbober [7]
2 years ago
9

Help!!!!!!!!! Difference between sperm and zygote​

Biology
2 answers:
Oliga [24]2 years ago
8 0

ZYGOTE IS DIPLOID CELL FORM WHEN TWO GAMETE CELLS ARE JOINED BY MEANS OF SEXUAL REPRODUCTION

SPERM IS THE MALE REPRODUCTIVE CELL,OR GAMETE IN ANISOGAMOUS FORMS OF SEXUAL REPRODUCTION.

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Setler [38]2 years ago
3 0

<em>zygote</em> is the diploid cell that results from the fertilization between an egg and sperm

<em>sperm</em> is the male reproductive cell that is responsible for a baby to born

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Answer:

Mutation.

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Duchenne muscular dystrophy is an X-linked recessive disease. A phenotypically normal couple wants to start a family. The woman’
Andreyy89

Answer:

\frac{1}{8}

Explanation:

From the question: Duchenne muscular dystrophy is an X-linked recessive disease.

Now for an X-linked recessive disorder to be affected by a male individual; it only requires the presence of only one copy of the recessive allele of the disease to be present BUT in a female individual. both copies of the recessive allele must be present.

Let the X-linked recessive disease(i.e Duchenne muscular dystrophy) be = (ⁿ)

However, we are told that the couples are normal and are unaffected. Therefore;

the male partner (XY) will be:   X^NY

the female partner (XY) will be: X^NX^N

Similarly, the question proceeds by telling us that: the woman's brother has the disease.

Definitely, it's possible that this unaffected woman is a carrier of the disease.

So, if she is a carrier; we have her traits to be: X^NX^n

NOW, if a cross exist between these couples; we have

X^NY     ×        X^NX^n

                     X^N                         Y

X^N                X^NX^N                  X^NY

X^n                 X^NX^n                   X^nY

So, we have offspring as follows:

X^NX^N  = normal unaffected female  

X^NY     = normal unaffected male

X^NX^n   = female carrier for the Duchenne muscular dystrophy disease

X^nY      = affected male with the Duchenne muscular dystrophy disease

So, the probability of the child to be affected with the disease = \frac{1}{4}

Also, the probability that the first child will be a male or a female = \frac{1}{2}

∴

the  probability that the couple’s first child will be affected = \frac{1}{4}*\frac{1}{2}

=\frac{1}{8}

4 0
3 years ago
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