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adelina 88 [10]
3 years ago
9

An athlete eats 75g of protein per day while training. How much protein will she eat during 25 days of training? Write your answ

er in kilograms.
Mathematics
2 answers:
polet [3.4K]3 years ago
4 0

75 \times 25 = 1875
The answer is 1.875 kilograms
Tanya [424]3 years ago
4 0
She will eat 1.875kg of protein while training for 25 days

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What add up to get 1 but multiplies to get -42
Tems11 [23]

Answer:

7 and -6

Step-by-step explanation:

7 + (-6) = 1

7 * (-6) = -42

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3 years ago
True or false? An obtuse triangle cannot be similar to an acute triangle.
daser333 [38]

Answer:

True

Step-by-step explanation:

an obtuse triangle is a big one, an acute triangle is a small one. They are both triangles, but they are not similar besides that

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I need help with this
WITCHER [35]

Answer:

8.1

Step-by-step explanation:

8.1 is the highest as you would look at the first number before the decimal and is the highest in this equation.

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3 years ago
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Need help with this....
Yakvenalex [24]

Answer:

\boxed{\dfrac{f(a+h)-f(a)}{h}=-3a^2-3ah-h^2}

Step-by-step explanation:

f(x)=-x^3+2\\\\\dfrac{f(a+h)-f(a)}{h}\\\\f(a+h)\to\text{substitute x = a + h}\\f(a)\to\text{substitute x = a}\\\\\dfrac{f(a+h)-f(a)}{h}=\dfrac{-(a+h)^3+2-(-a^3+2)}{h}\\\\\text{use}\ (x+y)^3=x^3+3x^2y+3xy^2+y^3\\\\=\dfrac{-(a^3+3a^2h+3ah^2+h^3)+2-(-a^3)-2}{h}\\\\=\dfrac{-a^3-3a^2h-3ah^2-h^3+2+a^3-2}{h}\\\\\text{combine like terms}

=\dfrac{(-a^3+a^3)-3a^2h-3ah^2-h^3+(2-2)}{h}\\\\=\dfrac{-3a^2h-3ah^2-h^3}{h}\\\\=\dfrac{h(-3a^2-3ah-h^2)}{h}\\\\=-3a^2-3ah-h^2

6 0
3 years ago
Benjamín made 3 times more than Alberto and Carlota 2 times more than Benjamín, so how much is it, help me
vichka [17]

Step-by-step explanation:

you are "hiding" some more information (like how much they made together).

without that we cannot calculate the actual values.

all I can do is set up the equations expressing the given relations between the parts of the total :

a = amount Alberto made

b = amount Benjamin made

c = amount Carlota made

b = 3×a

c = 2×b = 2× 3×a = 6×a

that's it.

your see ? now we need something that "ties" all 3 together, an equation of all 3 variables, where we can use the first 2 equations (by substitution) and then solve for the remaining third variable.

and that is missing.

if it is something like "together they made x", then we would have

a + b + c = x

a + 3a + 6a = x

10a = x

a = x/10

b and c we get then from the first 2 equations by simply using the calculated value of a :

b = 3×(x/10) = 3x/10

c = 6×(x/10) = 6x/10 = 3x/5

7 0
2 years ago
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