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irga5000 [103]
3 years ago
11

Find the value of x to the nearest tenth.

Mathematics
1 answer:
Komok [63]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Glad to help you ;)

If you have any questions about the way I solved it, don't hesitate to ask

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Hellp pls this is not a quiz
ra1l [238]

Answer:

The answer is D.

Step-by-step explanation:

Remember, think of what they would be like on a number line. The negative number closest to zero is greater than the negative numbers farther from zero. Any number that is to the left of a certain number is less than, if that makes any sense.

8 0
3 years ago
Y=6x - 11 -2x - 3y = -7
Ray Of Light [21]
<h2>Therefore x=2 and y= 1</h2>

Step-by-step explanation:

Given equations are

y = 6x -11                    and         -2x -3y = -7.........(2)

⇒y - 6x = -11.......(1)

Equation (2)× 3 - Equation (1)

-6x -9y -(y-6x) = -21 -(-11)

⇔-6x -9y-y+6x=-21+11

⇔-10y = -10

⇔y=1

Putting the value of y in equation (1) we get

1 = 6x -11

⇔x =2

Therefore x=2 and y= 1

3 0
3 years ago
Find the indicated limit, if it exists. limit of f of x as x approaches 9 where f of x equals x plus 9 when x is less than 9 and
SVEN [57.7K]

Answer:

B. 18

Step-by-step explanation:

For the function

f(x)=\left\{\begin{array}{l}x+9,\ \ x

we can find the value of the function for all x that are very close to 9 but are less than 9 and for all values of x that are very close to 9 but are greater than 9.

1. For x

\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(x+9)=9+9=18

2. For x\ge 9:

\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(27-x)=27-9=18

So, limit exists and is equal to 18.

8 0
3 years ago
What is the perimeter of the larger triangle?
Dmitriy789 [7]

42 ft

Source(s):

Dude trust me

4 0
2 years ago
Data on the blood cholesterol levels of 6 rats give mean = 85, s= 12. A 95% confidence interval for the mean blood cholesterol o
lana [24]

The <em><u>correct answer</u></em> is:

c)75.4 to 94.6

Explanation:

The formula for a confidence interval is:

\mu \pm z*(\frac{\sigma}{\sqrt{n}}),

where μ is the mean, z is the z-score associated with the level of confidence we want, σ is the standard deviation, and n is the sample size.

Our mean is 85, our standard deviation is 12, our sample size is 6, and since we want 95% confidence, our z-score is 1.96:

85\pm 1.96(\frac{12}{\sqrt{6}})=85\pm 9.6=85-9.6, 85+9.6=75.4, 94.6

4 0
3 years ago
Read 2 more answers
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