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Gala2k [10]
3 years ago
10

3-3-2-2-2 written as a whole number​

Mathematics
2 answers:
SpyIntel [72]3 years ago
5 0
The answer is 33,222
Andru [333]3 years ago
4 0

Answer:

I think this would be 33,222 I don't know I feel positive about this.

Step-by-step explanation:

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F (x)= x+ - 5x2 - 6x - 10
umka21 [38]

2x34 ds and search the scientific calculator and use it

Step-by-step explanation:

7 0
3 years ago
Round 13.2 to a whole number
sertanlavr [38]

round to 13 since you round down.

so the answer is 13

3 0
3 years ago
Help please ITS OF TRIGONOMETRY<br>PROVE ​
Flauer [41]

Answer:

The equation is true.

Step-by-step explanation:

In order to solve this problem, one must envision a right triangle. A diagram used to represent the imagined right triangle is included at the bottom of this explanation.  Please note that each side is named with respect to the angle is it across from.

Right angle trigonometry is composed of a sequence of ratios that relate the sides and angles of a right triangle. These ratios are as follows,

sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}

One is given the following equation,

\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0

As per the attached reference image, one can state the following, using the right angle trigonometric ratios,

sin(A)=\frac{a}{c}\\\\sin(B)=\frac{b}{c}\\\\cos(A)=\frac{b}{c}\\\\cos(B)=\frac{a}{c}

Substitute these values into the given equation. Then simplify the equation to prove the idenity,

\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0

\frac{\frac{a}{c}+\frac{b}{c}}{\frac{b}{c}+\frac{a}{c}}+\frac{\frac{b}{c}-\frac{a}{c}}{\frac{a}{c}-\frac{b}{c}}=0

\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}

Remember, any number over itself equals one, this holds true even for fractions with fractions in the numerator (value on top of the fraction bar) and denominator (value under the fraction bar).

\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}

\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{-(a-b)}{c}}{\frac{a-b}{c}}

1+(-1)=0

1-1=0

0=0

7 0
3 years ago
What is the common ratio of the sequence 80, 20, 5, 5/4 . . . .? What are the next three terms of the sequence?
I am Lyosha [343]
To find the common ratio in a geometric sequence, u divide the second term by  the first term. 20/80 = 1/4 <== common ratio

Terms are found in a geometric sequence by multiplying each number by the common ratio to get to the next number.

start with 80
80 * 1/4 = 80/4 = 20
20 * 1/4 = 20/4 = 5
5 * 1/4 = 5/4
5/4 * 1/4 = 5/16 <===
5/16 * 1/4 = 5/64 <===
5/64 * 1/4 = 5/256 <===
7 0
3 years ago
Read 2 more answers
60 is what percent of 72
Sedbober [7]
60 is 83% of 72.


60 divided by 12 is 5, and 72 divided by 12 is six.
5/6 equals 0.83
0.83 x 100 is 83, or 83%.

<span>Brainiest would be nice.</span>
8 0
3 years ago
Read 2 more answers
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