Can someone help me please ASAP PLEASE PLEASEEEEEE
2 answers:
S = standard
h = high quality
s + h = 840Subtract s from both sides.
h = -s + 840
Input h to the other equation.
2.7s + 4.4(-s + 840) = 2846
2.7s + -4.4s + 3696 = 2846
Subtract 3696 from both sides.
-1.7s = -850
Divide both sides by -1.7
s = 500
h = -500 + 840
h = 340
There were 500 downloads of the standard form
h = high quality
s + h = 840Subtract s from both sides.
h = -s + 840
Input h to the other equation.
2.7s + 4.4(-s + 840) = 2846
2.7s + -4.4s + 3696 = 2846
Subtract 3696 from both sides.
-1.7s = -850
Divide both sides by -1.7
s = 500
h = -500 + 840
h = 340
There were 500 downloads of the standard form
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Answer:
Yes altitudes are shown.
Two altitudes can be there depending upon the choice of base and altitude of triangle.
Step-by-step explanation:
First of all, let us have a look at the definition of an altitude in a triangle.
<em>Altitude </em>of any triangle is the perpendicular dropped (making a right angle with the side) on any side opposite to a vertex of triangle.
Here, in the given , we can see that the
is right angle.
i.e. <em>Altitudes are shown here.</em>
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Generalization about right triangles:
There can be two choices of altitudes in a right angled triangle depending upon the choice of base.
In the given triangle is right angle.
If we choose AB as the base of triangle, the vertex opposite to AB is C.
The side BC is at right angle to AB i.e. perpendicular dropped from vertex C to side AB. Therefore BC is the altitude.
Now, If we choose BC as the base of triangle, the vertex opposite to BC is A.
The side AB is at right angle to CD i.e. perpendicular dropped from vertex A to side BC. Therefore AB is the altitude.