All categories

1 year ago

Determine whether x=2 is a solution to the inequality -2x< -4

Mathematics

2 answers:

Grace [21]1 year ago

8 0

Answer:

Step-by-step explanation:

-2x<-4

x=2

-2×2<-4

-4<-4

which is not true.

Hence x=2 is not a solution.

nordsb [41]1 year ago

8 0

Answer: No

Step-by-step explanation: To determine whether x = 2 is a

solution to the inequality, substitute a 2 in for <em>x</em>.

So we have -2(2) < -4 or -4 < -4 which is a false statement.

No, 2 is not a solution to the inequality.

You might be interested in

Para calcular 1/7 de 2/5

dalvyx [7]

Answer: I'm willing to help you but, I don't get what your trying to ask.

4 0

2 years ago

Practice 7) fill in the blanks.

DiKsa [7]

(h,k) is the vertex

b/2a is the line of symmetry

a > 0 parabola opens upward, vertex is a minimum

a < 0 parabola opens downward, vertex is a maximum

My first answer was deleted lolol

7 0

2 years ago

Find the value of x

geniusboy [140]

-1, maybe or maybe not this is my first time doing this

7 0

2 years ago

Given that curl F = 2yi – 2zj + 3k, find the surface integral of the normal component of curl F (not F) over (a) the open hemisp

Dimas [21]

Use Stokes' theorem for both parts, which equates the surface integral of the curl to the line integral along the surface's boundary.

a. The boundary of the hemisphere is the circle $x^2+y^2=9$ in the plane $z=0$ , where the curl is $\mathrm{curl}\vec F=2y\,\vec\imath+3\,\vec k$ . Green's theorem applies here, so that

$\displaystyle\iint_S\mathrm{curl}\vec F\cdot\mathrm d\vec S=\int_{\partial S}\vec F\cdot\mathrm d\vec r=3\int_{x^2+y^2=9}\mathrm d\vec r$

which means the value of the line integral is 3 times the area of the circle, or $27\pi$ .

b. The closed sphere has no boundary, so by Stokes' theorem the integral is 0.

7 0

2 years ago

What is 3/30 simplified

Otrada [13]

Your answer will be 1/10. you divide 3 by the numerator and denominator <span />

6 0

2 years ago

Read 2 more answers