First term t(1)=(x-y)
common ratio =(x+y) (don't omit the parentheses)
then the nth term:
t(n)=(x-y)(x+y)^(n-1)
check:
t(1)=(x-y)(x+y)^(1-1)=(x-y)(x+y)^0=(x-y)(1)=(x-y)
t(3)=(x-y)(x+y)^(3-1)=(x-y)(x+y)^2
When n is small, t(n) can also be found by repeated multiplication of the common ratio (x+y)
Answer:
Last option
(AB)^2+(BC)^2=(AC)^2
Step-by-step explanation:
REASON because it follows Pythagoras theorem
27 since 27 is a factor of 54
Answer:
5
Step-by-step explanation:
p=(8)-3
p=5
15(100) + 5d+ 20(50) + 7d=d
1500+ 1000+ 12d=d
2500+12d=d
