Four apples.
Fifty percent - or half - of eight is four
Answer:
The measure of arc DEF is 204°
B is correct
Step-by-step explanation:
In a circle center at O.
∠DOF and ∠DEF are lie on same base but ∠DOF at center and ∠DEF on circle.
Thus, ∠DOF = 2 ∠DEF
minor ∠DOF = 2 x 78 = 156°
We need to find arc DEF.
DEF is central angle of major∠DOF
major∠DOF + minor ∠DOF = 360° (Complete angle at center)
major∠DOF + 156° = 360°
major∠DOF = 204°
major∠DOF is arc DEF.
Hence, The measure of arc DEF is 204°
Pretty sure it’s obtuse !
Answer:
(A) 0.297
(B) 0.595
Step-by-step explanation:
Let,
H = a person who suffered from a heart attack
G = a person has the periodontal disease.
Given:
P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15
Compute the probability that a person has the periodontal disease as follows:

(A)
The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.
(B)
Now if the probability of a person having a heart attack is, P (H) = 0.38.
Compute the probability that a person has the periodontal disease as follows:

Compute the probability of a person having a heart attack given that he or she has the disease:

The probability of a person having a heart attack given that he or she has the disease is 0.595.
No, I just took the test,
The answer would be
C. P(solid)22