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DIA [1.3K]
3 years ago
13

Question 6 options: What is the approximate area of a circle with a diameter of 56 cm? Use your calculator button for π. Round y

our answer FOUR decimal places. _________cm2
Mathematics
1 answer:
Andrew [12]3 years ago
8 0

The area of circle is 2463.0086 cm².

Step-by-step explanation:

Given,

Diameter of circle = 56 cm

Radius of circle = \frac{Diameter}{2}

Radius of circle = \frac{56}{2}=28\ cm

We know that;

Area of circle = \pi r^2

Area of circle = \pi *(28)^2

Area of circle = π * 784

Area of circle = 2463.00864041 cm²

Rounding off to four decimal places

Area of circle = 2463.0086 cm²

The area of circle is 2463.0086 cm².

Keywords: area, circle

Learn more about area at:

  • brainly.com/question/11416224
  • brainly.com/question/11638377

#LearnwithBrainly

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6 0
3 years ago
In RSM camp, there are four counselors for every fifty seven students and three teachers for every five counselors.
Ray Of Light [21]

Answer:

Students : Counselors : Teachers = 285: 20 : 12

Step-by-step explanation:

In the camp, the ratio of:

( C: S )  Counselors : Students   is  4   :  57

( T: C )  Teachers :   Counselors  is  3   :  5

To determine the ratio of   -  Students : Counselors : Teachers

Here given      -  C : S  = 4 : 57

Multiplying both sides by 5, we get

C: S  = 4 x 5  : 57 x 5  = 20 : 285

So, for every 20 counselors, there are 285 students      ...... (1)

Similarly, given   Teachers :   Counselors  is  3   :  5

Multiplying both sides by 4, we get

T  : C  = 3 x 4  : 5 x 4  = 12  : 20

So, for every 12  teachers, there are 20 Counselors      ...... (2)

Hence, in both equation 1 and 2 the number of counselors is same = 20 .

Hence, both the ratios acne be combined.

So we get C : S  = 20 : 285      and T : C  = 12: 20

Inverting the values

⇒  S : C  = 285 : 20         and C : T  = 20 : 12

or, S : C : T  = 285: 20 : 12

or, Students : Counselors : Teachers = 285: 20 : 12

Hence, for every 285 students there are 20 counselors and 12 teachers.

4 0
3 years ago
Ping's Ice Cream Palace offers a special sundae that contains over 2 kilograms of ice cream plus any number of toppings. Write a
hjlf

Let "x" represent the weight of the toppings. We know that we can have any number of toppings. This means that one may ask for no toppings at all too.

Now, we have been told that "S" is the weight of the special sundae in kilograms. This definitely included the "mandatory" 2 kilograms of ice cream. Therefore, S will be at-least equal to 2.

Thus, the inequality that describes S, the weight of the special sundae in kilograms at Ping's Ice Cream Palace is given as:

S\geq 2+x kilograms.

It can be seen that as x increases, S increases too and if an order does not want any toppings in it then the weight of the special sundae will be a minimum of 2 kg which is the weight of the ice cream.

7 0
3 years ago
Read 2 more answers
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