The domain of the function g(x)=l2xl +2 is all real numbers and the range is from (0,∞).
Given g(x)= l2xl +2
First of all we know that modulas gives two values for x<0 and x>=0.
The function g(x) if opened gives two values.
for x>=0 g(x)=2x+2
for x<0 g(x)=-2x+2
because we have not told about the description about x so we can put any value in the function.
So the domain is all real numbers.
Now when we take g(x)=2x+2 for x>=0
putting x=0 we get 2 and rest are positive values so the value of g(x) keeps increasing as we increase the value of x. So here range is [2,∞).
Now take g(x)=-2x+2 for x<0
putting smallest number starting from zero but not 0 we will get a number near to 0 but not zero and because when a negative number multiplies with -2 it becomes positive and increase the value of g(x) so here the range becomes (0,∞).
When we talk about overall range it will be [2,∞) ∪(0,∞)
it will be (0,∞).
Hence the domain of the function g(x) is all real numbers and range is from 0 to infinity.
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Answer:
natural
Step-by-step explanation:
Radioactive half-life is the time it takes for half an amount of radioactive material to decay into something else. In this case, it is assumed that the decay product is not radioactive or otherwise hazardous.
We must use the radioactive decay formula to determine at what time the radiation reaches a safe level.
A = Ao[e^(-0.693)(t)(t 1/2) where t 1/2 is the half-life, t is elapsed time, Ao is the original quantity, A is the future quantity.
We are given a half-life of 2.4 days , an Ao of 1.25 and an A of 1.00:
1.00 = (1.25)e^(-0.693)(2.4)t
1.00/1.25 = e^(-1.6632)t
0.8 = e^(-1.6632)t
t = 0.135 days = 3 hrs 15 min
This is the amount of time to a "safe level" using only radioactive decay, not venting or other means.
Answer:
C
Step-by-step explanation:
its obvious.... i literally says which axis is X