Hi dear,
log(x+3)-log10+logx+1=0
log(x+3)-1+logx+1=0
log(x+3)+logx=0
logx(x+3)=0
x(x+3)=10^0
x^2+3x-1=0
solve this equation that answers are:
X1= [ (13)^(1/2) - 3]/2
X1= [ (13)^(1/2) + 3]/2
Answer:
-30.6
Step-by-step explanation:
-3.(6+4.2)use distributive property:
-3×6=-18
-3×4.2=-12.6
Then solve what is in the parenthesis
(-18+-12.6)=-30.6
Answer:the answer is o.7.7
Step-by-step explanation:
Any number less than 4.7... and any number more than -2.6 :)
The point of elimination is to have one variable so example
3x + 2y = 4
7X + 3y = 5
1) Try to find a way to have one variable
7(3x + 2y = 4) ----> 21x + 14y = 28
-3(7x+ 3y = 5) -----> -21x -9y = -15
2) add
0 + 5y = 13
3) solve for the last variable
5y = 13
y = 13/5 = 2 3/5 = 2.8
4) Subsitute the variable to get the other one
3x + 2(2.8) = 4
3x + 5.6 = 4
3x = -1.6
x = 0.533333333 (continue)
The intersection would be 0.53 with a line above the 3 and 2.8. (0.5333 , 2.8)
Hope you understand!!
