The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
28/4 = 7...and since the price fell, it would be -7 per day
110 girls and 85 boys.
Subtract 1 from 195. Then divide by 2. 194/2 = 97. Then add 13 97+13=110. There are 110 girls.
You need to foil, The answer is D
Answer:
The number of feet she will travel back is 1 or 7 feet
Step-by-step explanation:
Here, we need to solve the quadratic equation
That will be as follows;
0 = x^2 -8x + 7
x^2-x-7x+ 7 = 0
x(x-1)-7(x-1) = 0
(x-1)(x-7) = 0
x = 1 or 7
The number of feet she will travel before coming back to the surface of the water is 1 or 7 feet
