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Alexeev081 [22]

4 years ago

14

If f(x) = x^2, which of the following describes the graph of f(x) - 5?

2 answers:

notka56 [123]4 years ago

8 0

Answer:

B

Step-by-step explanation:

12345 [234]4 years ago

7 0

In any given equation, a positive or negative number that isn't multiplied by a variable is called "b", or "y-intercept." Seeing as y-5 (f(x) is the same as y) isn't an equation, it probably means you need to add 5 to both sides to isolate y.
you end up with y=5, a horizontal line in which every "y" value in every set of points is equal to 5
Ex: (1,5),(2,5),(3,5)...
this means that your parent function of y=0 has a vertical shift upwards of five. hope I could help :)

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nirvana33 [79]

Answer:

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Step-by-step explanation:

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2 years ago

Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.

k0ka [10]

Answer:

Yuri is not correct.

Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = $\frac{3}{4}$ ,

$q(\frac{3}{4})=6(\frac{3}{4})^3+19(\frac{3}{4})^2-15(\frac{3}{4})-28$

= $6(\frac{27}{64})+19(\frac{9}{16})-15(\frac{3}{4})-28$

= $(\frac{162}{64})+(\frac{171}{16})-(\frac{45}{4})-28$

= $(\frac{162}{64})+(\frac{684}{64})-(\frac{720}{64})-\frac{1792}{64}$

= $-\frac{1666}{64}$

= $-\frac{833}{32}$ ≠ 0

Therefore, Yuri is not correct. x = $\frac{3}{4}$ can not be a root of the given expression.

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