Answer: Aleah i think the answer is g
Step-by-step explanation:
I should say that 13, 24, 14 are the next three numbers, because as you can see above the first(11) number is the third(12) number minus 1 and the fourth(23) is the second (22) plus 1 if you understand what I`m trying to say
n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
But you're already done....
I'm thinking you would have to add the probabilities that you choose a boy with you choose someone in the science club minus a boy in the science club. You can't count these people twice.
I'm getting 59%
(11+10-2)/32
