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kicyunya [14]
3 years ago
8

How do I find and round the principal square root of 8​

Mathematics
1 answer:
irga5000 [103]3 years ago
6 0

Answer: The square root of 8 is expressed as √8 in the radical form and as (8)½ or (8)0.5 in the exponent form. The square root of 8 rounded up to 8 decimal places is 2.82842712. It is the positive solution of the equation x2 = 8.

Step-by-step explanation:

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Answer:

124 degrees warmer

Step-by-step explanation:

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consider the graph of the following qudratic equation. y= -x^2 -10x + 24.What is the y-value of the vertex?
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Given that the quadratic equation is y=-x^{2}-10 x+24

We need to determine the y - value of the vertex.

<u>The x - value of the vertex:</u>

The x - value of the vertex can be determined using the formula,

x=-\frac{b}{2 a}

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Substituting these values, we get;

x=-\frac{(-10)}{2(-1)}

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<u>The y - value of the vertex:</u>

The y - value of the vertex can be determined by substituting the x - value of the vertex ( x = -5) in the equation y=-x^{2}-10 x+24

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2 years ago
Solve 3x-4= 7 you may use the flowchart to help you if you wish
laiz [17]

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Step-by-step explanation:

Given

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