PQ // BC
then
Angle P = Angle B, A is common angle the two triangles are similar
AP/AB = AQ/AC
8/18 = 12/ AC
AC = 12 * 18/8 = 27 (your ans: D)
AQ + QC = AC
QC = AC - AQ = 27 - 12 = 15 (if it was required)
tan60 = y/8
y = s tan60 = 8sqrt(3) (B)
Next time, post each question separately.
Step-by-step explanation:
2(2x + 1) = 3(x - 4)
4x+2=3x-12
4x-3x=--12-2
x=14
Distance = speed* time
D= constant rate *1/4 miles/hour
Answer:
2
Step-by-step explanation:
Given the question :
Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack bags should be identified without any food leftover, what is the greatest number of snack bags Serena can make?
Number of granolas = 6
Number of dried fruits = 10
Since the snackbag is to be designed in such a way that there should be no food leftover, the greatest number of snack bags Serena can make could be obtained by getting the highest common factor of (6 and 10)
____6____10
2___3____5
Here, the highest common factor of 6 and 10 is 2
Hence, the greatest number of snack bags she can make is 2.
Answer:
Step-by-step explanation:
∠E = ∠G
∠D= ∠F because it’s a parallelogram ==> D=F=2x+12 and E=G=5x
5x+2x+12=180
7x=168
X=24
Solution 2:
2*5x+2*(2x+12)=360
10x+4x+24=360
14x=360-24=336
X=336/14
X=24
