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bixtya [17]
3 years ago
14

Math question below where do i place

Mathematics
1 answer:
kotegsom [21]3 years ago
5 0
The two numbers of absolute value are negative three and positive three.
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Aliun [14]
A is the the answer for you
6 0
4 years ago
Is this a function yes or no
hjlf

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yep

Step-by-step explanation:

<h2>I am a  CHICKEN NUGGETS  WADDLE WADDLE</h2>
8 0
3 years ago
The standard form of an absolute value function is f(x) = ax-h1+k Which of the following represents the vertex?
blagie [28]

there's no "following"

3 0
3 years ago
Read 2 more answers
Barbara's gross earnings for the week ending on December 21 amount to \$1,100 . Her cumulative gross earnings for the year up th
zlopas [31]

Answer:

  • b) $44

Step-by-step explanation:

Barbara's cumulative gross earnings for the year up through her last pay date amount to 55000.

As per attached table this amount falls in 4% region ($50001 - $70000).

<u>Her tax per current pay period is:</u>

  • $1100*0.04 = $44

Correct choice is b)

6 0
3 years ago
A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
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