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3 years ago

What is the answer? Links will be reported. ( BRANLIEST )

Mathematics

2 answers:

qaws [65]3 years ago

7 0

Answer:

$- 1 \frac{1}{8} m + \frac{3}{10} \\$

Step-by-step explanation:

$\frac{7}{8} m + \frac{9}{10} - 2m - \frac{3}{5} \\ \frac{7}{8} m - 2m + \frac{9}{10} - \frac{3}{5} \\ \frac{7}{8} m - \frac{2m \times 8}{1 \times 8} + \frac{9}{10} - \frac{3 \times 2}{5 \times 2} \\ \frac{7m - 16m}{8} + \frac{9 - 6}{10} \\ - \frac{9}{8} m + \frac{3}{10} \\ - 1 \frac{1}{8} m + \frac{3}{10} \\$

Fudgin [204]3 years ago

7 0

Answer:

-1 1/8 m + 3/10 is the correct answer

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A surveyor sights the far bank of a river at an angle of 110° to the near bank. She then moves 75 feet upriver and sights the sa

Leya [2.2K]

Answer:

Correct answer is 54.82 ft.

Step-by-step explanation:

First of all, let us label the diagram and do the construction as per the attached answer image.

Let us consider $\triangle ABC$ :

$\angle B = 90^\circ\\\angle ACB = 180-110 = 70^\circ$

Let side AB = d ft and let side BC = x ft

We need to find AB to find the shortest distance across the river.

Using trigonometric identity of tangent:

$tan\theta = \dfrac{Perpendicular}{Base}$

$tan 70 = \dfrac{d}{x}\\\Rightarrow x = \dfrac{d}{tan70} = 0.36d ..... (1)$

Now, let us have a look at another right angled triangle ABD:

Let us consider $\triangle ABC$ :

$\angle B = 90^\circ\\\angle ADB = 180-150 = 30^\circ$

side AB = d ft and side BD = x+75 ft

Using trigonometric identity of tangent:

$tan\theta = \dfrac{Perpendicular}{Base}$

$tan 30 = \dfrac{d}{x+75}\\\text{Using equation (1)}:\\0.577 = \dfrac{d}{0.36d+75}\\\Rightarrow 0.207d + 43.27 = d\\\Rightarrow 0.793d = 43.27\\\Rightarrow d \approx 54.82\ ft$

Correct answer is 54.82 ft.

7 0

4 years ago

Show step by step explanation 9x-(6x+6)=5x-30

Shtirlitz [24]

Answer:

x=-18

Step-by-step explanation:

multiply the invisible 1 outside the parenthesis with the numbers inside. next combine like terms on the left side of the equation. then simplify the equation. then divide -2x by -36. then multiply -1 to your answer and the outcome gives -18

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3 years ago

PLEASE HELP!!! A bridge has a weight limit of 5000 kg. What is the heaviest load that a pickup truck weighing 4500 pounds could

jeka57 [31]

Answer:

6500 lb

Step-by-step explanation:

The load limit of the bridge is ...

(5000 kg)(2.2 lb/kg) = 11,000 lb

The total of truck and trailer cannot exceed this value, so the trailer's weight cannot exceed ...

11,000 lb -4,500 lb = 6,500 lb . . . max trailer weight

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3 years ago

While her husband spent 2½ hours picking out new speakers, a statistician decided to determine whether the percent of men who en

AVprozaik [17]

Answer:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

$z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057$

$p_v =P(Z>0.0057)=0.4977$

The p value is a very high value and using the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.

Step-by-step explanation:

1) Data given and notation

$X_{M}=23$ represent the number of men that said they enjoyed the activity of Saturday afternoon shopping

$X_{W}=8$ represent the number of women that said they enjoyed the activity of Saturday afternoon shopping

$n_{M}=66$ sample of male selected

$n_{W}=23$ sample of demale selected

$p_{M}=\frac{23}{66}=0.34848$ represent the proportion of men that said they enjoyed the activity of Saturday afternoon shopping

$p_{W}=\frac{8}{23}=0.34782$ represent the proportion of women with red/green color blindness

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the percent of men who enjoy shopping for electronic equipment is higher than the percent of women who enjoy shopping for electronic equipment , the system of hypothesis would be:

Null hypothesis: $p_{M} \leq p_{W}$

Alternative hypothesis: $p_{M} > p_{W}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

Where $\hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{23+8}{66+23}=0.34831$

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057$

4) Statistical decision

Using the significance level provided $\alpha=0.05$ , the next step would be calculate the p value for this test.

Since is a one side right tail test the p value would be:

$p_v =P(Z>0.0057)=0.4977$

So the p value is a very high value and using the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.

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3 years ago

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Dvinal [7]

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3 years ago