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3 years ago

CE TASK

Mathematics

1 answer:

diamong [38]3 years ago

7 0

Determine how much money did the carpenter start with

The total money with the carpenter is $318.4

Given:

let

x = total money with the carpenter

Bags of sand = 7/8 of x

= 7/8x

Money remaining = x - 7/8x

= (8x-7x) / 8

= 1/8x

Bags of bunting bags = 1/2 of 1/8x

= 1/2 × 1/8x

= 1/16x

Money left = $19.90

Total money = bags of sand + bag of bunting flag + money left

x = 7/8x + 1/16x + 19.90

x = (14x + x) / 16 + 19.90

x = 15/16x + 19.90

x - 15/16x = 19.90

16x - 15x / 16 = 19.90

x/16 = 19.90

divide both sides by 1/16

x = 19.90 ÷ 1/16

= 19.90 × 16/1

= 318.4

Therefore, the total money with the carpenter is $318.4

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Ostrovityanka [42]

Answer:

2.25

Step-by-step explanation:

The computation of the number c that satisfied is shown below:

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$f^i(c) = \frac{f(b) - f(a)}{b -a }$

After this,

$f(x) = \sqrt{x} \\\\ f^i(x) = \frac{1}{2}x ^{\frac{1}{2} - 1} \\\\ = \frac{1}{2}x ^{\frac{-1}{2}$

$f^i(x) = \frac{1}{{2}\sqrt{x} } = f^i(c) = \frac{1}{{2}\sqrt{c} } \\\\\a = 0, f (a) = f(o) = \sqrt{0} = 0 \\\\\ b = 9 , f (b) = f(a) = \sqrt{9} = 3\\$

After this,

Put the values of a and b to the above equation

$f^i(c) = \frac{f(b) - f(a)}{b - a} \\\\ \frac{1}{{2}\sqrt{c} } = \frac{3 -0}{9-0} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{3}{9} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{1}{3} \\\\ \sqrt[2]{c} = 3\\\\\sqrt{c} = \frac{3}{2} \\\\ c = \frac{9}{4}$