Please help me please

Need helpwith this math

solniwko [45]

Answer: -0.6, -1/4 (-0.25), -0.15

Step-by-step explanation: the farther away from 0, going left, the smaller the number.

7 0

3 years ago

Pamela is 12 years younger than Jiri. The sum of their ages is 80. What is Jiri's age?<br> years old

vfiekz [6]

80/2= 40
46-34= 12
So Pamela is 34 & Jiri is 46

7 0

3 years ago

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

7 0

4 years ago

The equation 6x - 5y = 14 is written in standard form. Which point lies on

dimaraw [331]

Answer= H (-1, -4)

Explanation= 6(-1) - 5(-4) = 14
(-6) + (20) = 14
14=14 * it works !
GOODLUCK!

4 0

3 years ago

A rectangle measures 54 feet by 72 feet. What is the length, in feet, of

igomit [66]

length (l) =54

breath (b) =72

l²+b²= diagonal²..........(Pythagoras theorem) and (all sides of rectangle are 90degree)

(54)²+(72)²=diagonal²

2916+5184=diagonal²

8100=diagonal²

90= diagonal.............(taking square root)

length of diagonal is 90ft

i hope it helps

have a nice day and thanks for asking this question

6 0

3 years ago