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Lorico [155]
2 years ago
8

Write an equation in slope-intercept form of the line with slope −4/5 that contains the point (−5, −4).

Mathematics
1 answer:
Tomtit [17]2 years ago
6 0
From the slope our equation so far is
y = -4/5x + B
Now we find B
-------------------------
To find be all we have to is substitute (-5,-4) for x and y in <span>3x + 5y = 15 
</span>(-4) - (-4/5)( -5) = b
-8 = b
---------------------------------
So your equation would be y = -4/5x - 8
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bija089 [108]
59×2=118 cost of bill.
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6 0
3 years ago
Factor 5x4 - 30x2 - 135.
lakkis [162]

Answer:

-175

Step-by-step explanation:

5x4=20

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I hope this helps!

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3 years ago
4 cos²x – 1=0<br><br> What is the solution?
andreev551 [17]

Answer:

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$x=\frac{2\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{4\pi }{3}+2\pi n, n \in \mathbb{Z}$

or

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Step-by-step explanation:

4\text{cos}^2(x)-1=0\\4\text{cos}^2(x)=1\\

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So, when cos(x) is equal to

$\frac{1}{2}   \text{ and } -\frac{1}{2}$    ?

For

$cos(x)=\frac{1}{2} $

We are talking about x = 60º and x = 300º, Quadrant I and IV, respectively. In radians:

$x=\frac{\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{5\pi }{3}+2\pi n, n \in \mathbb{Z}$

or

$x=\frac{\pi}{3}+\pi n, n \in \mathbb{Z} $

For

$cos(x)=-\frac{1}{2} $

We are talking about x = 120º and x = 240º, Quadrant II and III, respectively. In radians:

$x=\frac{2\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{4\pi }{3}+2\pi n, n \in \mathbb{Z}$

or

$x=\frac{2\pi }{3}+\pi n, n\in \mathbb{Z}$

6 0
3 years ago
Help Me With These <br> #Geometry
Damm [24]
They are mad as easy try it on your own your answer is suppose to be 80
5 0
3 years ago
Your auto insurance is $900 per quarter. What should you use as the monthly average? The auto insurance is a fixed expense, but
Airida [17]

Answer:

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4 0
3 years ago
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