Answer:
The Transport Layer Security (TLS) protocol adds a layer of security on top of the TCP/IP transport protocols. TLS uses both symmetric encryption and public key encryption for securely sending private data, and adds additional security features, such as authentication and message tampering detection
Greeting's!
It Will Ask You To Input An Old Password "Current" Password And A "New" Password After That Is Done You Can Use The "New" Password Instead Of The "Old" Password.
Answer and Explanation:
Given data:
Distance (D) = 40 KM
Speed of light in the fiber =Distance/ speed of light in the fiber
a) Delay (P) = Distance/ speed of light in the fiber
= (40,000 Meters/2×108 m/s)
=( 40×103 Meters/2×108 m/s)
Propagation delay (P) = 0.0002 seconds or 200 microseconds
b)
if propagation delay is 0.0002 Seconds roundup trip time (RTT) will be 0.0004 Seconds or 400 micro Seconds
Essentially since transmission times and returning ACKs are insignificant all we really need is a value slightly greater than 0.0004 seconds for our timeout value.
c)
The obvious reasons would be if the data frame was lost, or if the ACK was lost. Other possibilities include extremely slow processing on the receive side (late ACK).
Or Extremely Slow Processing of the ACK after it is received back at the send side.
When the increment or decrement operator is placed before the operand (or to the operand's left), the operator is being used in prefix mode. Postfix mode on the other hand is when the increment or decrement operator is placed after the operand (or to the oper and's right) .
Only one daemon (server application) can bind to a port. The second one will fail.
