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ryzh [129]
3 years ago
12

PLEASE SAY IF THE NUMBERS ARE RATIONAL OR IRRATIONAL. PLEASE NO LINKS.

Mathematics
2 answers:
Annette [7]3 years ago
8 0

Answer:

i think the third one and the last box is rational and the other one are not

Step-by-step explanation:

Gekata [30.6K]3 years ago
8 0
/22 is irrational
9/17 is rational
-/81 is rational
-20.-^80= I think is rational
18*sign* = irrational
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katie can build three staircases to make 36 obstacles against the other player. how many staircases will she need to make 24 obs
son4ous [18]

Answer:

i think it'd be 2

Step-by-step explanation:

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2 years ago
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Help please ill give 12 points for the right answer
Aneli [31]

It’s it four I think hope it helps

8 0
3 years ago
Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x + 2) f(x) = (x – 2)(x + 2) f(x) = (x + 1)(x – 2)
strojnjashka [21]

we know that

If the vertex is on the y-axis, then the x-coordinate of the vertex is equal to zero

we are going to verify the vertex of each one of the functions to determine the solution

Remember that

The equation in vertex form of a vertical parabola is equal to

y=a(x-h)^{2} +k

where

(h,k) is the vertex

if a>0 -------> the parabola open upward (vertex is a minimum)

if a -------> the parabola open downward (vertex is a maximun)

<u>case A)</u> f(x)=(x-2)^{2}

This is a vertical parabola open upward

the vertex is the point (2,0)

therefore

The function f(x)=(x-2)^{2}  does not have a vertex on the y-axis

<u>case B)</u> f(x)=x(x+2)

f(x)=x(x+2)=x^{2}+2x

convert to vertex form

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)+1=x^{2}+2x+1

Rewrite as perfect squares

f(x)+1=(x+1)^{2}

f(x)=(x+1)^{2}-1

the vertex is the point (-1,-1)

therefore

The function f(x)=x(x+2) does not have a vertex on the y-axis

<u>case C)</u> f(x)=(x-2)(x+2)

f(x)=(x-2)(x+2)=x^{2}-2^{2}

f(x)=x^{2}-4

the vertex is the point (0,-4)

The x-coordinate of the vertex is equal to zero

therefore

The function f(x)=(x-2)(x+2) has a vertex on the y-axis

<u>case D)</u> f(x)=(x+1)(x-2)

f(x)=(x+1)(x-2)\\ \\f(x)= x^{2}-2x+x-2 \\ \\f(x)= x^{2} -x-2

convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)+2= x^{2} -x

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)+2+0.25= x^{2} -x+0.25

f(x)+2.25= x^{2} -x+0.25

Rewrite as perfect squares

f(x)+2.25= (x-0.50)^{2}

f(x)=(x-0.50)^{2}-2.25

the vertex is the point (0.5,-2.25)

therefore

The function f(x)=(x+1)(x-2) does not have a vertex on the y-axis

<u>the answer is</u>

f(x)=(x-2)(x+2)

6 0
3 years ago
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3. Given PQ = 7x - 3 and QR = 32 – 2x and PR = 59. What is the value of x? What is the value of PQ? What is the value of QR? Be
olga2289 [7]

Answer:

wag po kayo mag bibigay ng points na marami

Kasi ma iiscam po kayo

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Each floor of a hotel as r rooms. On 8 floors, there are a total of 256 rooms. Write an equation to represent this situation
Natalka [10]

Answer:

256/8 = r

Step-by-step explanation:

256 room between 8 floors so divide the number of rooms by each floor to work out r

256 divided by 8 equals r

3 0
3 years ago
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