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Alex_Xolod [135]
3 years ago
10

Ricky is filling an 8 inch by 4 1/2 inch rectangular box with packing peanuts. The peanuts are cubes that come in two different

sizes ,1 cubic inch and 1/8 inch .How many peanuts of each size are needed to fill the box?
Mathematics
1 answer:
Marina86 [1]3 years ago
6 0
Ok, so we can fill the part of the box that corresponds to the 8x4 inches with the boxes that are 1 cubic inch - that wound be 8x4, that is 32 such boxes.

then the rest would be 8x \frac{1}{2} inches, that is 4 cubic inches.

In order to fill in 4 cubic inches with  \frac{1}{8} inches boxes we calculate:

4/ \frac{1}{8}=4*8=32  So it's also 32 such small boxes!

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First, we can start off by finding the GCF of the denominator and the numerator. To do so, we need to list the factors of each of them and find the common ones.

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We can see that our common factors are 1 and 2, considering that both the numerator and denominator has the same factors (1 and 2). Since we have our common factors, we need to find the greatest. Which is the greatest out of 1 and 2? The GCF is 2 because it is bigger than 1.

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Third, now we can revise our fraction and turn it into the simplest form. Take the two numbers you just got above us and put them in their numerator and denominator spot. You should get: \frac{5}{4}

Answer in fraction form: \fbox {5/4}
Answer in decimal form: \fbox {1.25}
Answer in mixed number form: \fbox {1 1/4}
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