Answer:
The height of the big cone is double the one in the small cone
h2 = 2h1
Step-by-step explanation:
Given that:
- The volume of the small cone: 5 cubic inches
- The volume of the big cone: 10 cubic inches
As we know, the volume of a cone is as following:
V = (1/3)*area of the base*height
If the base diameter are unchanged => area of the base of the two cones are unchanged and from the given information, the volume of the big cone is double the volume of the small cone. So the height of the big cone is double the one in the small cone
<=> h2 = 2h1
Answer:
Option B
Option E
Step-by-step explanation:
By the use of following postulates we can prove the two right triangles to be congruent.
1). HA - [Equal hypotenuse and an cute angles]
2). LL - [Two legs should be equal]
3). LA - [One leg and one angle must be equal]
4). ASA - [Two angles and the side containing these angles should be equal]
In the given right triangles,
1). OJ ≅ IL
2). ∠O ≅ ∠I
3). ∠J ≅ ∠L
Therefore, two postulates HA, ASA will be applicable for the congruence of the two triangles given.
Options A and E will be the answer.
Answer:
Monday he walked 
Wednesday he walked 
Friday he walked 
Step-by-step explanation:
Given Mason walked on Monday, Wednesday and Friday. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday. we have to find how far he walked each day.
distances are 
that are 0.75, 0.25 and 0.17 respectively.
Now, he didn't walk farthest on Monday and also walked less on Friday than Monday.
∴ Less distance travelled is 
which is on friday and then 
on monday.
Rest distance which is 
on wednesday.
Hence, Monday he walked
Wednesday he walked
Friday he walked
