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3 years ago

Will get Brainliest!!!!!!! Is -8 an integer?

Mathematics

2 answers:

Scorpion4ik [409]3 years ago

8 0

Answer:

it is a integer

fractions are not integers

Step-by-step explanation:

Elden [556K]3 years ago

6 0

Step-by-step explanation:

yes indeed -8 is an integer number

integer number consists of negative number too

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liq [111]

Answer:

2) b-1

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5 0

2 years ago

What is the product? (2y + 3) (3y^2 +4y + 5)

Furkat [3]

Answer:

6y³ + 17y² + 22y + 15

Step-by-step explanation:

(2y + 3)(3y² + 4y + 5)

6y³ + 8y² + 10y + 9y² + 12y + 15

6y³ + 8y² + 9y² + 10y + 12y + 15

6y³ + 17y² + 22y + 15

8 0

2 years ago

Read 2 more answers

Y^2 + 18y - 41 = 0 Y= Y=

lana66690 [7]

Answer:

y= -9+√122, or -9 - √122

Step-by-step explanation:

You have to solve the equation for y to find each variable of the quadratic and applying the quadratic formula.

after solved, I got the answer as decimal,

y = 2.0453610.....

i simpler form : y = 2.05

Also, an answer can be y= -9+√122, or -9 - √122

6 0

2 years ago

What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?

DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. $\frac{n(n-3)}{2}$

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

$\frac{n(n-3)}{2}$

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = $\frac{6(6-3)}{2}$

= $\frac{18}{2}$

= 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = $\frac{7(7-3)}{2}$

= $\frac{28}{2}$

= 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = $\frac{30(30-3)}{2}$

= $\frac{810}{2}$

= 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = $\frac{n(n-3)}{2}$

The number of diagonals in a n-gon is $\frac{n(n-3)}{2}$

7 0

3 years ago

Please can I have an explanation also, I am terrible at these kinds of questions!

wlad13 [49]

Answer:

The fraction of the beads that are red is

Step-by-step explanation:

Algebraic Expressions

A bag contains red (r), yellow (y), and blue (b) beads. We are given the following ratios:

r:y = 2:3

y:b = 5:4

We are required to find r:s, where s is the total of beads in the bag, or

s = r + y + b

Thus, we need to calculate:

$\displaystyle \frac{r}{r+y+b} \qquad\qquad [1]$

Knowing that:

$\displaystyle \frac{r}{y}=\frac{2}{3} \qquad\qquad [2]$

$\displaystyle \frac{y}{b}=\frac{5}{4}$

Multiplying the equations above:

$\displaystyle \frac{r}{y}\frac{y}{b}=\frac{2}{3}\frac{5}{4}$

Simplifying:

$\displaystyle \frac{r}{b}=\frac{5}{6} \qquad\qquad [3]$

Dividing [1] by r:

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+y/r+b/r}$

Substituting from [2] and [3]:

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+3/2+6/5}$

Operating:

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{\frac{10+3*5+6*2}{10}}$

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{10+15+12}$

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{37}$

The fraction of the beads that are red is $\mathbf{\frac{10}{37}}$

8 0

2 years ago