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3 years ago

PLSS HELP ILL GIVE POINTS!!!!

Mathematics

1 answer:

Gala2k [10]3 years ago

4 0

Answer:

y=16x+36

Step-by-step explanation:

cleaning services start at $36 for one hour and add $16 to total price per hour.

16(1)+36=52

16(2)+36=68

16(3)+36=84

16(4)+36=100

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1. Write an equation for a line in slope intercept form that passes through (0,5) and has a slope of 2

SIZIF [17.4K]

Answer:

equation of line: y = 2x + 5

Explanation:

using the formula:

y - y1 = m(x - x1)

y - 5 = 2(x - 0)

y - 5 = 2x

y = 2x + 5

6 0

2 years ago

Read 2 more answers

Jerome, kevin and seth shared a submarine sandwhich. Jerome ate 1/2 of the sandwich , kevin ate 1/3 of the sandwich, and seth at

Paul [167]

Given:

Jerome ate 1/2 of the sandwich , Kevin ate 1/3 of the sandwich, and Seth ate the rest.

To find:

The ratio of jerome's share to kevin's share to seth's share.

Solution:

Jerome ate 1/2 of the sandwich. So,

Jerome's share = $\dfrac{1}{2}$

Kevin ate 1/3 of the sandwich. So,

Kevin's share = $\dfrac{1}{3}$

Seth ate the rest. So,

Seth's share = $1-\dfrac{1}{2}-\dfrac{1}{3}$

= $\dfrac{6-3-2}{6}$

= $\dfrac{1}{6}$

The ratio of jerome's share to kevin's share to seth's share is:

$\dfrac{1}{2}:\dfrac{1}{3}:\dfrac{1}{6}$

To simplify the ratio multiply the ratio by 6.

$\dfrac{1}{2}\times 6:\dfrac{1}{3}\times 6:\dfrac{1}{6}\times 6$

$3:2:1$

Therefore, the ratio of jerome's share to kevin's share to seth's share is 3:2:1.

8 0

3 years ago

Yanika is teaching a swim class. She needs to divide the class into teams for a relay race. There is 18 students.

coldgirl [10]

A possible sizes two teams of 9 or 9 teams of 2, 6 teams of 3 or 3 teams of 6

B yes 3 lanes could divide her 18 students by putting 6 people in each lane
18/3= 6

8 0

3 years ago

Which number needs to be added to the table to keep it proportional?

Paraphin [41]

20 because it is counting by fives (5,10,15,20) and 5x4=20

4 0

3 years ago

Solve the triangle: α = 40°, β = 35°, and a = 10.

luda_lava [24]

The triangle: α = 40°, β = 35°, and a = 10. is b = 8.9, γ = 105°, c = 15.0

If A, B, and C are the measurements of the angles of an oblique triangle, and a, b, and c are the lengths of the sides opposite of the corresponding angles, then the ratios of the a side’s length to the sine of the angle opposite the side must all be the same.

a/ sin A = b/ sin B = c/ sin C

Using Angle sum property in a triangle we have,

α+β+ γ = 180

40+35+ γ=180

γ= 180-75

γ= 105°

Now,

c/ sin γ= a/ sin α

c/ sin 105= 10/ sin 40

c/ 0.96592 = 10 /0.6427

c = 15

again,

b/ sin β= a/ sin α

b/ sin 35= 10/ sin 40

b/0.5737= 15.559

b= 8.92

Learn more about sine law here:

brainly.com/question/17289163

#SPJ1

4 0

3 years ago