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ikadub [295]
3 years ago
6

a. About how far is it from Amarillo to Oklahoma City? Explain your reasoning. b. Driving at a constant speed of 70 miles per ho

ur, will it be possible to make this trip in 3 hours? Explain how you know.​
Mathematics
1 answer:
balu736 [363]3 years ago
8 0

Answer:

They are 260 miles apart. No it would not be possible.

Step-by-step explanation:

If they are 260 miles apart and you drive at a constant speed on 70mph. You will have to 260/70 which = 3.7 or 4 so it would not be possible.

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Help with these math questions please help me thank you!
Reptile [31]

Step-by-step explanation:

1.(2,3)

2.No

3.1st quadrant

4.5

5.Yes

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6 0
4 years ago
A girl's feet are negative 2 over 4 yards from the surface of a pool. A boy's feet are negative 3 over 4 yards from the surface
frozen [14]
The girls are closer. Her feet are 1/2 the distance away from the surface pool, the boys are 3/4 away.
6 0
3 years ago
How do I solve this using the Pythagorean theorem​
charle [14.2K]

Answer:

x=3

Step-by-step explanation:

First would need to convert the radical into a number.

And since if you have a perfect square of a radical it goes outside the square root sign, you would take the 3 and square it to make 9 and then take the 2 inside the square root sign and multiply so you have the square root of 18|

Since we have \sqrt{18} as the Leg c we would need to square it, squaring a square root sign would just cause them to be cancelled out and you being left with 18, afterwards find the square of 3, which is 9

18-9=9

square root of 9 = 3

3 0
3 years ago
A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular
Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2}(AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2} x^{2} (2 sin 22.5° cos 22.5°)

= \frac{1}{2} x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

=2.828x^{2}

Area required for mulch = circular area - area of the gazebo

=3.14x^{2} -2.828x^{2}

=0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312x^{2} × 1.5

=0.468x^{2}

Hence, total cost g(m) = 0.468x^{2}.

4 0
3 years ago
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