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Neko [114]
2 years ago
11

What value should be added to both sides for completing the square in this equation?

Mathematics
1 answer:
Mila [183]2 years ago
3 0

Hey there!

x^2 + 4x = 12

SUBTRACT 12 to BOTH SIDES

x^2 + 4x - 12 = 12 - 12

SIMPLIFY IT

x^2 + 4x - 12 = 0

FACTOR the LEFT SIDE of your EQUATION

(x - 2)(x + 6) = 0

• EQUATION #1: x - 2 = 0

OR

• EQUATION #2: x + 6 = 0

SIMPLIFY IT

• EQUATION #1 answer: x = 2

OR

• EQUATION #2 answer: x = -6

OVERALL ANSWER: x = 2 or x = -6

YOUR ANSWER: x = 2 (Option A.)

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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I need help please?!!!!
shusha [124]

Answer:

n = -6

Step-by-step explanation:

-3n + 9 = 27 (Given)

-3n + 9 - 9 = 27 - 9 (Subtraction Property of Equality)

-3n = 18 (Simplify)

\frac{-3n}{-3} = \frac{18}{-3} (Division Property of Equality)

n = -6 (Simplify)

5 0
2 years ago
The cost of a rental is 160 for 5 days. At this rate, how much does it cost to rent the tent for one day?
Olin [163]

the answer is $32 you divide 160 by 5

8 0
3 years ago
Calculator
Sedaia [141]

Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24

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3 years ago
99 points AND BRAINLIEST answer to the person who can do this for me. I WILL REPORT ANY DUMB ANSWERS! PLEASE HELP ASAP!
Evgen [1.6K]
ΔADC ≅ ΔBCD (SAS congruency)

∠AED ≅ ∠BEC (opposite angles)

ΔAED ≅ ΔBEC (ASA congruency)

Therefore DE <span>≅ CE (corresponding sides of the two congruent triangles AED and BEC)</span>
8 0
3 years ago
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