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3 years ago

Help please....................

Mathematics

2 answers:

Darina [25.2K]3 years ago

6 0

Answer:

Step-by-step explanation:

mars1129 [50]3 years ago

6 0

That’s challenging!!

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Increasing the sample size while keeping the same confidence level has what effect on the margin of error? A. Increases the marg

DiKsa [7]

Answer:

C. Decreases the margin of error and hence increases the precision

Step-by-step explanation:

If we select a sample by Simple Random Sampling in a population of “infinite” size (a population so large that we do not know its size exactly), then the margin of error is given by

$\bf E=\frac{ZS}{\sqrt{n}}$

where

Z = The Z-score corresponding to the confidence level

S = The estimated standard deviation of the population

n = the size of the sample.

As we can see, since n is in the denominator of the fraction and the numerator is kept constant, the larger the sample size the smaller the margin of error, so the correct choice is:

C. Decreases the margin of error and hence increases the precision

4 0

3 years ago

According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

UNO [17]

Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

Let $\hat p$ = sample proportion of Americans who can order a meal in a foreign language

The z-score probability distribution for sample proportion is given by;

Z = $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( $\hat p$ > 0.50)

P( $\hat p$ > 0.06) = P( $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ > $\frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } }$ ) = P(Z > 0.85) = 1 - P(Z $\leq$ 0.85)

= 1 - 0.80234 = 0.19766

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

4 0

3 years ago

WILL MARK BRAINLIEST

Zanzabum

Answer:

A.) (x + 2) and (2x - 1)

Step-by-step explanation:

So from the video i just watch this is how its done

3 (2x^2 + 3x - 2) = 0

4 and -1 gives you 3 and you divide them by a which is 2

4/2 (2/1) and -1/2 then you write them from the bottom to top

(x + 2) and (2x - 1)

Answer:

B.) 20 (x + 5) (x - 5) = 0

Step-by-step explanation:

20 (x^2 - 25) = 0

20 (x + 5) (x - 5) = 0

8 0

3 years ago

Tiago tem uma extensa coleção de livros ele os deixa organizados em uma estante, sparados por gênero. seu gênero favorito, suspe

Andreyy89

Guys help me I’m stuck in this question also it’s in my homework

6 0

3 years ago

Carlos wants to buy some new video games. Each game he buys costs him 36$. Is the relationship between the number of games carlo

baherus [9]

Answer:

Yes.

Step-by-step explanation:

In a direct proportional relationship, as one object gets larger, the other object gets larger as well. This fits that definition, as when the amount of video games bought increases, so does the amount of money spent.

5 0

3 years ago