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Elanso [62]
3 years ago
13

Joey got up at 6:55 A.M. and left for school at 7:35 A.M. How long did it take Joey to get ready for school?

Mathematics
1 answer:
maw [93]3 years ago
3 0

Answer:

It took Joey 40 minutes to get ready for school.

Step-by-step explanation:

Since there are 60 minutes in an hour and Joey woke up at 6:55, you add 5 minutes to 35 minutes to get your answer.

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every evening jenna empties her pockets and puts her change in a jar. At the end of the week she counts her money. One week she
Darya [45]
Let Q= the number of quarters and D= the number of dimes.
Q+D= 40 coins
0.25Q+0.1D= $7.75
Rewrite equation 1 as: D = 40-Q and substitute into equation 2
0.25Q+0.1(40-Q)= 7.75 Simplify the left side
0.25Q+4-0.1Q= 7.75 Subtract 4 from both sides
0.25Q-0.1Q= 3.75 Convime like terms on left side
0.15Q= 7.75 Divide both sides by 0.15
Q=25 and D= 40-Q
D= 40-25 which is 15
So Jenna had 25 quarters and 15 dimes.
<span>To check multiply 25 x 25 and 15x10 which equals 625 and 150 this equals 775 so this is 7.75</span>
8 0
3 years ago
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xenn [34]

Answer:

ASA

Step-by-step explanation:

In the 2 triangles

∠J = ∠L

side OJ = side IL

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The triangles are congruent by the angle/side/angle (ASA ) postulate

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A history test is worth 100 points. There are 26 total questions. There are vocabulary questions that are worth 2 points each an
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3 years ago
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3 years ago
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1. The data given below includes data from 42 ​candies, and 7 of them are red. The company that makes the candy claims that 33​%
jeyben [28]

Answer:

The 95% confidence interval for true proportion of red candies is (5%, 27%).

The true proportion of red candies made by the company is different from 33%.

Step-by-step explanation:

The hypothesis to determine whether the claim made by the candy company is correct or not is:

<em>H</em>₀: The true proportion of red candies made by the company is 33%, i.e. <em>p</em> = 0.33.

<em>Hₐ</em>: The true proportion of red candies made by the company is different from 33%, i.e. <em>p</em> ≠ 0.33.

A (1 - <em>α</em>)% confidence interval can be constructed to check this claim.

The decision rule is:

If the confidence interval consists the null value then the null hypothesis will not be rejected. Otherwise it will be rejected.

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The information provided is:

<em>n</em> = 42

<em>X</em> = number of red candies = 7

Compute the sample proportion of candies that are red as follows:

\hat p=\frac{X}{n}=\frac{7}{42}=0.167

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table for the critical value.

Compute the 95% confidence interval for true proportion of red candies as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.167\pm 1.96\times \sqrt{\frac{0.167(1-0.167)}{42}}\\=0.16\pm0.1137\\=(0.0463, 0.2737)\\\approx(0.05, 0.27)

The 95% confidence interval for true proportion of red candies is (5%, 27%).

The confidence interval does not contains the null value.

Thus, the null hypothesis will be rejected at 5% level of significance.

Conclusion:

The true proportion of red candies made by the company is different from 33%.

7 0
3 years ago
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