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daser333 [38]
2 years ago
15

PLEASE HELP ME!!! IT IS MATH YALL

Mathematics
2 answers:
Katarina [22]2 years ago
3 0

Answer:

my question is i get everything right also btw answer is A

Step-by-step explanation:

Alina [70]2 years ago
3 0

Answer:

hi the answer is the first one

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PLEASE HELP!!!!!! This is very important to me PLEASE HELP ASAP and if you help me god bless you
defon

Answer:

try the 3rd one

Step-by-step explanation:

if it's not right then i'm sorry

5 0
3 years ago
Read 2 more answers
For the polynomial function ƒ(x) = x4 − 16x2, find the zeros. Then determine the multiplicity at each zero and state whether the
ddd [48]
Our function f(x) can be rewritten if we factor out a common x^2 from each term:
f(x) = x^2(x^2-16)
Now inside the parentheses we have a polynomial of the form a^2 - b^2, or the difference of two perfect squares, which can be factored as (a+b)(a-b) so we have:
f(x)=x^2(x-4)(x+4)
Setting our function equal to zero gives us the roots x = 0, x = 4, and x = -4.
The multiplicity of the root zero is two since it occurs twice, and the others are one since they occur only once. If you graph the function you can see that it will only touch the x-axis at x = 0, but will cross the x-axis at x = 4 and x = -4.
5 0
4 years ago
Need Help With This​
podryga [215]

Answer:

4n-13

Step-by-step explanation:

Terms= -13 (constant)

Coefficient= 3, -5, 6

Like term= 3n, -5n, 6n

3n-13-5n+6n

3n+6n-5n-13

9n-5n-13

4n-13

Hope this helps ;) ❤❤❤

4 0
3 years ago
The approximate distance between K and L is units. The approximate distance between L and J is units. If you join all three poin
ss7ja [257]

Answer:

The answer is below

Step-by-step explanation:

The distance between two points A(x₁, y₁) and B(x₂, y₂) on the coordinate plane is given by:

AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\

Point J is at (-3, 3), point K is at (4, 3) and point L is at (1, -1). Hence:

The distance between K and L = KL = \sqrt{(-1-3)^2+(1-4)^2} =5\ units

The distance between J and L = JL = \sqrt{(-1-3)^2+(1-(-3))^2} =4\sqrt{2} \ units

The distance between K and J = JK = \sqrt{(3-3)^2+(-3-4)^2} =7\ units

Therefore, the perimeter of triangle JKL is:

Perimeter = KL + JL + JK = 5 + 4√2 + 7 = 17.66 units

8 0
3 years ago
X ≤ 8<br><br><br> x &gt; 8<br><br><br> x &lt; 8<br><br><br> x ≥ 8
katovenus [111]

Answer:

x < 8

Step-by-step explanation:

the dot isnt filled so symbol wont have a line under it

line moving left of 8 so less than 8.

6 0
3 years ago
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