Supposing we begin with n=1, the first few terms of this arith sequence are
5, 1, -3, -7, and so on. 4 is the common difference.
Let this number be represented by the variable "n"
product of 4 and n is multiplying4 and n
4 * n = 5.6
divide 4 to both sides to isolate the variable on one side
n=1.4
2f +4f +2 -3
combine the like terms to get 6f-1
so yes they are equivalent
2f+4f+2-3 at f=3 would also be 17
Answer:
10
Step-by-step explanation:
<u><em>y = -4 </em></u>
<u><em>x = 6 </em></u>
<em><u>x-y = 6-(-4) = 6+4 = 10</u></em>
<em><u /></em>
(It might also have helped immensely if you had been listening
when this was being explained in class.)
The first pipe fills 1/20 of the tank each minute.
The second pipe fills 1/30 of the tank each minute.
Operating together, the two pipes fill ( 1/20 + 1/30 ) of the tank each minute.
In order to add these fractions (or any fractions), you need a common denominator.
For these particular ones, ' 60 ' is a good choice.
( 1/20 + 1/30 ) = ( 3/60 + 2/60) = 5/60 = 1/12
The rate of work is 1/12 tankful per minute .
The most sensible choice for the time is 12 minutes.
R x T = W
( 1/12 tankful per minute ) x ( 12 minutes ) = 1 full tank
