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solniwko [45]
3 years ago
6

There are seven performers who will present their comedy acts this weekend at a comedy club. How many different ways are there t

o schedule their​ appearances?
Mathematics
1 answer:
bazaltina [42]3 years ago
4 0
7!=5040
.....................
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Round 717.25 to the nearest tenth.
Mashutka [201]

Answer:

717.3

Step-by-step explanation:

717.25

717.3

5 0
3 years ago
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The average allowsnce money of Ernest jack David and mike is 123 per month per person. The average allowance of Ernest jack and
Evgesh-ka [11]

Answer:

Ernest gets 194 monthly allowance

Step-by-step explanation:

* Lets revise the rule of the average

- Average = The sum ÷ the total number

- Assume that the allowances money of Ernest, Jack, David and Mike

  are E, J, D, M respectively

∵ The average allowance money of Ernest jack David and mike is

   123 per month per person

∴ 123 = (E + J + D + M) ÷ 4

- Multiply both sides by 4

∴ E + J + D + M = 492 ⇒ (1)

∵ The average allowance of Ernest jack and David is 159 per month

    per person

∴ 159 = (E + J + D) ÷ 3

- Multiply both sides by 3

∴ E + J + D = 477 ⇒ (2)

- Subtract equation(2) from equation (1) to find M

∴ M = 15

* <em>Mike's monthly allowance is 15</em>

∵ David's monthly allowance is 2 less than mikes

∴ D = M - 2

∵ M = 15

∴ D = 15 - 2 = 13

∴ <em>David's monthly allowance is 13</em>

∵ Mikes monthly allowance is 1/18 of jacks

∴ M = \frac{1}{18} × J

∴ 15 = \frac{1}{18} × J

- Multiply both sides by 18

∴ J = 270

* <em>Jack's monthly allowance is 270</em>

- Substitute the values of D , J in equation (2) to find E

∵ D = 13 and J = 270

∵ E + J + D = 477

∴ E + 270 + 13 = 477

∴ E + 283 = 477

- Subtract 283 from both sides

∴ E = 194

* <em>Ernest's monthly allowance is 194</em>

*<em> Ernest gets 194 monthly allowance</em>

4 0
3 years ago
Ivan has a lemonade stand. He keeps records of his daily profits and how many customers he had that day. The scatter plot shows
ale4655 [162]

Answer: i believe that the answer would be b

8 0
3 years ago
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Write the quadratic equation whose roots are 4 and 5, and whose leading coefficient is 4.
Umnica [9.8K]

Answer:

<u>Answer</u><u>:</u><u> </u><u>4</u><u>x</u><u>²</u><u> </u><u>-</u><u> </u><u>9</u><u>x</u><u> </u><u>+</u><u> </u><u>2</u><u>0</u><u> </u>

Step-by-step explanation:

• General quadratic equation:

{ \rm{ {x}^{2}  - (sum \: of \: roots)x + (product \: of \: roots) }}

• sum of roots → 4 + 5 = 9

• product of roots → 4 × 5 = 20

• substitute:

{ \boxed{ \rm{4 {x}^{2}  - 9x + 20 }}}

3 0
3 years ago
Please help me on this it would be very much appreciated
azamat
Answer: -24

-140/14+140/-10
-10/1+-14/1
-10+-14/1
=-24
3 0
3 years ago
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