I believe the correct answer from the choices listed above is the last option. The true statement about the graph of x < 4 would be that an open circle on 4 and all numbers to the left shaded. Hope this answers the question. Have a nice day. Feel free to ask more questions.
Answer:
m∠4 = 55°
Step-by-step explanation:
From the figure attached,
m∠DBC = m∠BCA + m∠BAC [Exterior angle of a triangle equals the sum of the remote interior angles]
m∠4 = 30° + 25° = 55°
Therefore, m∠4 = 55° will be the answer.
Answer:
25pi
Step-by-step explanation:
If the circle has a diameter of 10, it has an radius of 5. The area of a circle is pi*r^2. If r=5, then it is 25pi.
Answer:
(a)
Given: A line passes through the points (3, -2) and (6, 2)
Point slope form: An equation of line passing through two points and is given by:
.....[1] where m is the slope of the line.
Calculate first the slope of the line:
Slope(m) =
Substitute the given points;
Substitute the value of m in [1] ;
......[1]
therefore, the equation of line in point slope form is,
(b)
to find the standard form of the equation [1]
Multiply both sides by 3 in [1] we get;
using distributive property;
3y + 6 = 4x -12
Subtract 3y to both sides we get;
3y + 6 -3y = 4x - 12 - 3y
Simplify:
6 = 4x - 3y -12
Subtract 6 from both sides we get;
0 = 4x - 3y -12-6
Simplify:
4x - 3y - 18 =0
Therefore, the standard form of the equation is; 4x - 3y - 18 =0
Answer:
- If x=0 , then f(0)=2
- If f(x)=0 , then x = -1
Step-by-step explanation:
First lets assume that the y axis is called the<em> ordinate axis </em>and the x axis is the <em>abscissa axis</em>
Then:
- The first question asks for the y value in the <em>ordinate axi</em>s that corresponds to the x = 0 value. To begin:
You must start to locate the x=0 value on the abscissa axis, its located in the center of the axis.
Then you start for searching the y value that the curve takes when it passes through the ordinate axis, this correspond to the value of the function f(x) on x=0. The value according to the graph is y=2.
Then , you located the point (0,f(0))=(0,2).
- The second question asks for the x value in the abscissa axis that corresponds to the f(x)=y=0 value. To begin this, you start the other way around:
You must locate the y=0 value on the ordinate axis, its also located in the center of the axis.
Then you start for searching the x value that the function needs to take the y=0 value. According to the graph the value of x that the function needs is x = -1
Then, you located the point where f(x)=y=0, its (-1,0).
An example is attached to the answer